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Unit 3.4 Structural Analysis
Adv Higher Unit 3 Topic 4 Unit 3.4 Structural Analysis 1 1 1 1
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Unit 3.4 Structural Analysis
Introduction This topic explores various methods used in the Structural Analysis of organic molecules starting with Elemental Analysis and Mass Spectrometry. Unit 3.4 Structural Analysis
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Unit 3.4 Structural Analysis
Elemental Analysis 1 Empirical formulas are determined by combustion analysis: Carbon, Hydrogen, Sulphur & Nitrogen can all be determined by combustion analysis. Other elements can be determined by other methods. KHS Chemistry Unit 3.4 Structural Analysis
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Unit 3.4 Structural Analysis
Elemental Analysis 2 Calculation is same as taught at Standard Grade. KHS Chemistry Unit 3.4 Structural Analysis
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Unit 3.4 Structural Analysis
Empirical Formula 1 A substance was analysed and gave these results: C 47.6% ; H 4.76% ; N 22.2% and O 25.4% by mass. What is the empirical formula? In 100 g there will be 47.6 / 12 moles of C = 3.97 4.76 / 1 moles of H = 4.76 22.2 / 14 moles of N = 1.59 25.4 / 16 moles of O = 1.59 KHS Chemistry Unit 3.4 Structural Analysis
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Unit 3.4 Structural Analysis
Empirical Formula 2 Ratio of C:H:N:O is 3.97: 4.76: 1.59: 1.59 Divide by smallest number to simplify Simplifying ratio: : 2.99: 1: 1 Whole number ratio is 5: 6: 2: 2 Empirical formula is C5H6N2O2 KHS Chemistry Unit 3.4 Structural Analysis
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Unit 3.4 Structural Analysis
Mass Spectrometry A mass spectrometer does three things vaporises a minute sample of compound (10-10 g) ionises the vaporised molecules separates and analyses the ions, produced when the molecules fall apart, according to their mass/charge ratio, giving a mass spectrum KHS Chemistry Unit 3.4 Structural Analysis
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Unit 3.4 Structural Analysis
Mass Spectrometer KHS Chemistry Unit 3.4 Structural Analysis
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Unit 3.4 Structural Analysis
Molecular Ion A high-energy electron can dislodge an electron from a bond, creating a radical cation (a positive ion with an unpaired e-). Molecular ion m1+ + m2. M M+. m1. + m2+ m1+ + m2 Fragmentation then occurs. KHS Chemistry Unit 3.4 Structural Analysis
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Unit 3.4 Structural Analysis
Common Fragments Some fragments are more stable and, therefore, more likely Fragment m or m/z H2O CH CH3CH CH3CO C7H7+ + 91 KHS Chemistry Unit 3.4 Structural Analysis
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Unit 3.4 Structural Analysis
Tropylium Ion C7H7+ + 91 This ion is a particularly stable ion and is often the most abundant peak (Base Peak). Its presence indicates that the original molecule contained a benzene ring with a carbon attached - often a very useful aid to the identification of the overall molecule. KHS Chemistry Unit 3.4 Structural Analysis
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Unit 3.4 Structural Analysis
The Mass Spectrum Masses are graphed or tabulated according to their relative abundance. KHS Chemistry Unit 3.4 Structural Analysis
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Unit 3.4 Structural Analysis
Example 1a m/z 80 60 100 40 20 rel abundance H3C CH CH2 CH3 2-METHYLPENTANE KHS Chemistry Unit 3.4 Structural Analysis
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Unit 3.4 Structural Analysis
Example 1b m/z 80 60 100 40 20 rel abundance H3C CH CH2 CH3 86 M+. The main use of a mass spectrum (at Advanced Higher ) is to identify the Molecular ion. KHS Chemistry Unit 3.4 Structural Analysis
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Unit 3.4 Structural Analysis
Example 1c m/z 80 60 100 40 20 rel abundance 71 H3C CH CH2 CH3 15 CH3+ C5H11+ Occasionally you can be asked to identify possible fragments. KHS Chemistry Unit 3.4 Structural Analysis
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Unit 3.4 Structural Analysis
Example 1d m/z 80 60 100 40 20 rel abundance H3C CH CH2 CH3 57 29 C4H9+ C2H5+ C2H3+ 27 Unstable fragments will often rearrange themselves to form more stable molecules. KHS Chemistry Unit 3.4 Structural Analysis
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Unit 3.4 Structural Analysis
Example 1e The detailed analysis of a mass spectrum is best left to experienced operators with years of experience. KHS Chemistry Unit 3.4 Structural Analysis
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Unit 3.4 Structural Analysis
Use of Mass Spectra At Advanced Higher, the main (only?) use of mass spectra is to determine the molecular formula of the molecule. m/z 80 60 100 40 20 rel abundance H3C CH CH2 CH3 86 M+. IR Spectroscopy and NMR Spectroscopy will be used to identify the actual structure of the molecule. Unit 3.4 Structural Analysis
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High Resolution Mass Spectrometer
Some modern Mass Spectrometers can now determine masses to 5 or 6 decimal places. This is accurate enough to differentiate between molecules of the ‘same mass’. Eg molecules with a mass of ‘44’ could be: C3H8 C2H4O CO or CN2H4 A more accurate measurement of mass from the spectrometer could be C3H8 C2H4O CO2 CN2H4 Unit 3.4 Structural Analysis
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