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Bellwork 5 2 1.) 50 2.) 32 3.) 80 4.) 128 4 2 4 5 8 2.

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Presentation on theme: "Bellwork 5 2 1.) 50 2.) 32 3.) 80 4.) 128 4 2 4 5 8 2."— Presentation transcript:

1 Bellwork 5 2 1.) 50 2.) 32 3.) 80 4.) 128 4 2 4 5 8 2

2 Solving Equations with a radical
Solve for a 1.) a2 = 36 2.) a2 = 49 3.) a2 = 60 4.) a2 = 80

3 Solving Equations with a radical
Solve for a 1.) a2 = 36 a = 36 a = 6, or -6

4 Solving Equations with a radical
Solve for a 2.) a2 = 49 a = 49 a = 7, or -7

5 Solving Equations with a radical
Solve for a 3.) a2 = 60 a = 60 a = , or

6 Solving Equations with a radical
Solve for a 4.) a2 = 80 a = 80 a = , or

7 Objective To be able to use the Pythagorean Theorem to find the lengths of the sides of a Right Triangle.

8 Area of a Square Area = Length * Width Length = 4 Width = 4 Area = 16

9 Areas of 3 squares 3 X 3 4 X 4 5 X 5

10 Arrange them into a triangle
5 X 5 4 X 4 3 X 3

11 Now make your squares 1.) 3,4,5 in length Cut out 3 squares that are:
First Draw the Squares on your paper Cut out 3 squares that are: 1.) 3,4,5 in length Arrange the sides so they form a Right Triangle.

12 Pythagorean Theorem In the 3,4,5 triangle add up the areas of the 2 smallest squares and compare that to the area of the largest square.

13 Pythagorean Theorem Area = 25 Area =16 = 25 Area = 9

14 First Draw the Squares on your paper
Now do #2 and #3. Now make your squares First Draw the Squares on your paper Outline 3 squares that are: 1.) 3,4,5 in length 2.) 6,8,10 in length 3.) 6,7,8 in length

15 Pythagorean Theorem 2.) 6,8,10 in length
Area = 100 Area =36 = 100 Area = 64

16 Pythagorean Theorem 3.) 6,7,8 in length
Area = 64 Area =49 = 64 Area = 36

17 Pythagorean Theorem What did you find????

18 Pythagorean Theroem a2 + b2 = c2
The sum of the areas of the 2 smaller squares equals the area of the largest square. This is TRUE for all Right Triangles a2 + b2 = c2

19 Pythagorean Theorem Area = c2 Area =a2 c a a2 + b2 = c2 b Area = b2

20 Find c if a2 + b2 = c2 1.) a=6, b= 8 2.) =c2

21 1.) Find the Hypotenuse a2 + b2 = c2 = c2 = c2 100 = c2 10 = c

22 2.) Find the Hypotenuse a2 + b2 = c2 = c2 = c2 289 = c2 17 = c

23 Find c if a2 + b2 = c2 3.) a=12,b=16 4.) =c2 Now you do these

24 3.) Find the Hypotenuse a2 + b2 = c2 = c2 = c2 400 = c2 20 = c

25 4.) Find the Hypotenuse a2 + b2 = c2 = c2 = c2 625 = c2 25 = c

26 Pythagorean Theorem What relationship exists between the lengths of the sides of a Right Triangle??

27 Pythagorean Theorem In a Right Triangle, the sum of the smallest sides squared is equal to the largest side squared. a2 + b2 = c2 where c is the longest side The longest side is known as the hypotenuse of the triangle.

28 Pythagorean Theorem a2 + b2 = c2 32 + 42 = 52 9 + 16 = 25 25 = 25
= 25 25 = 25 Where sides (a & b) are the shortest sides and side c is the hypotenuse.

29 a = 6 Find a if b = 8 & c = 10 a2 + b2 = c2 a2 + 82 = 102

30 Find a if a2 + b2 = c2 1.) c=10, b= 8 2.) c=20,b=16 3.) a2+152=172 4.) a2+242=252

31 1.) Find a a2 + b2 = c2 a = 102 a = 100 a2 = 36 a = 6

32 2.) Find a a2 + b2 = c2 a = 202 a = 400 a2 = 144 a = 12

33 3.) Find a a2 + b2 = c2 a = 172 a = 289 a2 = 64 a = 8

34 4.) Find a a2 + b2 = c2 a = 252 a = 625 a2 = 49 a = 7

35 Find a if a2 + b2 = c2 1.) c=10, b= 8 1.) a=6 2.) c=20,b=16 2.) a=12

36 Expression with radicals
Evaluate b2 - 4ac When a =1, b= -2, c=-3 (-2)2 - 4(1)(-3) = = 4

37 Expression with radicals
Evaluate b2 - 4ac When a =4, b= 5, c=1 (5)2 - 4(4)(1) 9 = 3 Your Turn

38 Classwork Worksheet 9.1 homework: page 455 (7-34)


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