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Section 2.3 Calculus AP/Dual, Revised Β©2017

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Presentation on theme: "Section 2.3 Calculus AP/Dual, Revised Β©2017"β€” Presentation transcript:

1 Section 2.3 Calculus AP/Dual, Revised Β©2017 viet.dang@humbleisd.net
Product Rule Section 2.3 Calculus AP/Dual, Revised Β©2017 2/24/2019 5:48 AM Β§2.3: Product Rule

2 Derivative (not being simplified)
Guess The Rule Equation Derivative (not being simplified) 1) 𝒅 𝒅𝒙 𝟐 𝒙 𝟐 πŸ“+πŸ’π’™ 2) 𝒅 𝒅𝒙 πŸ‘π’™βˆ’πŸ 𝒙 𝟐 (πŸ“+πŸ’π’™) 3) 𝒅 𝒅𝒙 𝒙 ( 𝒙 𝟐 +𝟐) 4) 𝒅 𝒅𝒙 𝒙 𝟐 𝐬𝐒𝐧 𝒙 𝐜𝐨𝐬 𝒙 5) 𝒅 𝒅𝒙 𝒇 𝒙 π’ˆ 𝒙 2/24/2019 5:48 AM Β§2.3: Product Rule

3 The Product Rule β€œFirst d-second plus second d-first”
2/24/2019 5:48 AM Β§2.3: Product Rule

4 The Product Rule 𝒅 𝒅𝒙 𝒇 𝒙 π’ˆ 𝒙 =𝒇 𝒙 π’ˆ β€² 𝒙 +π’ˆ 𝒙 𝒇 β€² 𝒙
𝒅 𝒅𝒙 𝒇 𝒙 π’ˆ 𝒙 =𝒇 𝒙 π’ˆ β€² 𝒙 +π’ˆ 𝒙 𝒇 β€² 𝒙 β€œFirst times the derivative of the second plus the second times the derivative of the first” Many times, there can be more than one derivative can be taken for a differentiable function. These derivatives imply continued continuity (like the first derivative): First Derivative: π’šβ€²=𝒇′(𝒙) = π’…π’š 𝒅𝒙 = 𝒅 𝒅𝒙 𝒇 𝒙 Second Derivative: π’šβ€²β€²=𝒇′′(𝒙) = 𝒅 𝟐 π’š 𝒅 𝒙 𝟐 = 𝒅 𝟐 𝒅 𝒙 𝟐 𝒇 𝒙 Third Derivative: π’šβ€²β€²β€²=𝒇′′′(𝒙) = 𝒅 πŸ‘ π’š 𝒅 𝒙 πŸ‘ = 𝒅 πŸ‘ 𝒅 𝒙 πŸ‘ 𝒇 𝒙 Fourth Derivative: π’šβ€²β€²β€²= 𝒇 (πŸ’) (𝒙)= 𝒅 πŸ’ π’š 𝒅 𝒙 πŸ’ = 𝒅 πŸ’ 𝒅 𝒙 πŸ’ 𝒇 𝒙 nth Derivative: π’š (𝒏) = 𝒇 (𝒏) (𝒙) = 𝒅 𝒏 π’š 𝒅 𝒙 𝒏 = 𝒅 𝒏 𝒅 𝒙 𝒏 𝒇 𝒙 2/24/2019 5:48 AM Β§2.3: Product Rule

5 Proof of Product Rule 2/24/2019 5:48 AM Β§2.3: Product Rule

6 Proof of Product Rule 2/24/2019 5:48 AM Β§2.3: Product Rule

7 Example 1 Solve for the derivative of 𝒇 𝒙 = 𝒙 𝟐 πŸπ’™βˆ’πŸ‘ 2/24/2019 5:48 AM
Β§2.3: Product Rule

8 Example 2 Solve for the derivative of 𝒇 𝒙 = (βˆ’πŸπ’™ πŸ’ +πŸ“ 𝒙 𝟐 +πŸ’) βˆ’πŸ‘ 𝒙 𝟐 +𝟐 2/24/2019 5:48 AM Β§2.3: Product Rule

9 Your Turn Solve for the derivative of 𝒇 𝒙 = 𝒙 𝟐 +𝟏 𝒙 πŸ‘ +πŸ‘
2/24/2019 5:48 AM Β§2.3: Product Rule

10 Example 3 Solve for the derivative of 𝒇 𝒙 =πŸ‘ 𝒙 πŸ‘ 𝐬𝐒𝐧 𝒙
Β§2.3: Product Rule

11 Example 4 Solve for the derivative of 𝒇 𝒙 =𝐬𝐒𝐧 𝒙 𝐜𝐨𝐬 𝒙
Β§2.3: Product Rule

12 Your Turn Solve for the derivative of 𝒇 𝒙 =πŸπ’™ 𝐬𝐒𝐧 𝒙 by using the Product Rule 2/24/2019 5:48 AM Β§2.3: Product Rule

13 Acceleration Acceleration can be defined as the second derivative of the position function or the first derivative of the velocity of the function Rate of Change of Velocity 𝒇 𝒕 = 𝒗 β€² 𝒕 = 𝒂 β€²β€² 𝒕 2/24/2019 5:48 AM Β§2.3: Product Rule

14 Example 5 The position of an object is defined by the equation, π’š= 𝟏 πŸ’ 𝒕 πŸ’ + 𝒕 𝟐 . What is the acceleration of the object at 𝒕=𝟐? 2/24/2019 5:48 AM Β§2.3: Product Rule

15 Example 6 Given π’…π’š 𝒅𝒙 =πŸ“ 𝒙 πŸ’ βˆ’πŸ‘π’™, solve for 𝒅 πŸ’ π’š 𝒅 𝒙 πŸ’
Β§2.3: Product Rule

16 Your Turn Given 𝒇′′(𝒙)=πŸ”π’™+πŸπŸ• 𝒙 βˆ’πŸ , solve for 𝒇 πŸ’ 𝒙 2/24/2019 5:48 AM
Β§2.3: Product Rule

17 AP Multiple Choice Practice Question 1 (non-calculator)
If 𝒇 β€²β€² 𝒙 =πŸ‘ 𝒙 𝟐 +πŸ”π’™+πŸ’, solve for 𝒇 (πŸ’) 𝒙 (A) 𝟎 (B) πŸ” (C) πŸπ’™+πŸ” (D) πŸ”π’™+πŸ” 2/24/2019 5:48 AM Β§2.3: Product Rule

18 AP Multiple Choice Practice Question 1 (non-calculator)
If 𝒇 β€²β€² 𝒙 =πŸ‘ 𝒙 𝟐 +πŸ”π’™+πŸ’, solve for 𝒇 (πŸ’) 𝒙 Vocabulary Connections and Process Answer and Justifications 2/24/2019 5:48 AM Β§2.3: Product Rule

19 AP Multiple Choice Practice Question 2 (non-calculator)
Find the derivative of 𝒙 𝟐 𝒇 𝒙 . (A) 𝒙 𝒙 𝒇 β€² 𝒙 +𝟐 𝒇 𝒙 (B) πŸπ’™ 𝒇 β€² 𝒙 (C) 𝒙 𝒙 𝒇 𝒙 +𝟐 𝒇 β€² 𝒙 (D) 𝒙 𝟐 𝒇 β€² 𝒙 2/24/2019 5:48 AM Β§2.3: Product Rule

20 AP Multiple Choice Practice Question 2 (non-calculator)
Find the derivative of 𝒙 𝟐 𝒇 𝒙 . Vocabulary Connections and Process Answer and Justifications 2/24/2019 5:48 AM Β§2.3: Product Rule

21 Assignment Page all, 13, 17, 31, 39, 63, 67A, 91, 93, 97 2/24/2019 5:48 AM Β§2.3: Product Rule


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