Download presentation
Presentation is loading. Please wait.
1
Section 2.3 Calculus AP/Dual, Revised Β©2017 viet.dang@humbleisd.net
Product Rule Section 2.3 Calculus AP/Dual, Revised Β©2017 2/24/2019 5:48 AM Β§2.3: Product Rule
2
Derivative (not being simplified)
Guess The Rule Equation Derivative (not being simplified) 1) π
π
π π π π π+ππ 2) π
π
π ππβπ π π (π+ππ) 3) π
π
π π ( π π +π) 4) π
π
π π π π¬π’π§ π ππ¨π¬ π 5) π
π
π π π π π 2/24/2019 5:48 AM Β§2.3: Product Rule
3
The Product Rule βFirst d-second plus second d-firstβ
2/24/2019 5:48 AM Β§2.3: Product Rule
4
The Product Rule π
π
π π π π π =π π π β² π +π π π β² π
π
π
π π π π π =π π π β² π +π π π β² π βFirst times the derivative of the second plus the second times the derivative of the firstβ Many times, there can be more than one derivative can be taken for a differentiable function. These derivatives imply continued continuity (like the first derivative): First Derivative: πβ²=πβ²(π) = π
π π
π = π
π
π π π Second Derivative: πβ²β²=πβ²β²(π) = π
π π π
π π = π
π π
π π π π Third Derivative: πβ²β²β²=πβ²β²β²(π) = π
π π π
π π = π
π π
π π π π Fourth Derivative: πβ²β²β²= π (π) (π)= π
π π π
π π = π
π π
π π π π nth Derivative: π (π) = π (π) (π) = π
π π π
π π = π
π π
π π π π 2/24/2019 5:48 AM Β§2.3: Product Rule
5
Proof of Product Rule 2/24/2019 5:48 AM Β§2.3: Product Rule
6
Proof of Product Rule 2/24/2019 5:48 AM Β§2.3: Product Rule
7
Example 1 Solve for the derivative of π π = π π ππβπ 2/24/2019 5:48 AM
Β§2.3: Product Rule
8
Example 2 Solve for the derivative of π π = (βππ π +π π π +π) βπ π π +π 2/24/2019 5:48 AM Β§2.3: Product Rule
9
Your Turn Solve for the derivative of π π = π π +π π π +π
2/24/2019 5:48 AM Β§2.3: Product Rule
10
Example 3 Solve for the derivative of π π =π π π π¬π’π§ π
Β§2.3: Product Rule
11
Example 4 Solve for the derivative of π π =π¬π’π§ π ππ¨π¬ π
Β§2.3: Product Rule
12
Your Turn Solve for the derivative of π π =ππ π¬π’π§ π by using the Product Rule 2/24/2019 5:48 AM Β§2.3: Product Rule
13
Acceleration Acceleration can be defined as the second derivative of the position function or the first derivative of the velocity of the function Rate of Change of Velocity π π = π β² π = π β²β² π 2/24/2019 5:48 AM Β§2.3: Product Rule
14
Example 5 The position of an object is defined by the equation, π= π π π π + π π . What is the acceleration of the object at π=π? 2/24/2019 5:48 AM Β§2.3: Product Rule
15
Example 6 Given π
π π
π =π π π βππ, solve for π
π π π
π π
Β§2.3: Product Rule
16
Your Turn Given πβ²β²(π)=ππ+ππ π βπ , solve for π π π 2/24/2019 5:48 AM
Β§2.3: Product Rule
17
AP Multiple Choice Practice Question 1 (non-calculator)
If π β²β² π =π π π +ππ+π, solve for π (π) π (A) π (B) π (C) ππ+π (D) ππ+π 2/24/2019 5:48 AM Β§2.3: Product Rule
18
AP Multiple Choice Practice Question 1 (non-calculator)
If π β²β² π =π π π +ππ+π, solve for π (π) π Vocabulary Connections and Process Answer and Justifications 2/24/2019 5:48 AM Β§2.3: Product Rule
19
AP Multiple Choice Practice Question 2 (non-calculator)
Find the derivative of π π π π . (A) π π π β² π +π π π (B) ππ π β² π (C) π π π π +π π β² π (D) π π π β² π 2/24/2019 5:48 AM Β§2.3: Product Rule
20
AP Multiple Choice Practice Question 2 (non-calculator)
Find the derivative of π π π π . Vocabulary Connections and Process Answer and Justifications 2/24/2019 5:48 AM Β§2.3: Product Rule
21
Assignment Page all, 13, 17, 31, 39, 63, 67A, 91, 93, 97 2/24/2019 5:48 AM Β§2.3: Product Rule
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.