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Packet #26 The Precise Definition of a Limit
Math 180 Packet #26 The Precise Definition of a Limit
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ex: What is the distance between 1 and 3 on the number line?
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ex: What is the distance between 1 and 3 on the number line?
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ex: What is the distance between 1 and 3 on the number line?
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ex: What is the distance between -2 and 3 on the number line?
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ex: What is the distance between -2 and 3 on the number line?
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ex: What is the distance between -2 and 3 on the number line?
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ex: What is the distance between π₯ and 2 on the number line
ex: What is the distance between π₯ and 2 on the number line? Remember: distances are positive.
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ex: What is the distance between π₯ and 2 on the number line
ex: What is the distance between π₯ and 2 on the number line? Remember: distances are positive.
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ex: What is the distance between π₯ and 2 on the number line
ex: What is the distance between π₯ and 2 on the number line? Remember: distances are positive.
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ex: What is the distance between π₯ and 2 on the number line
ex: What is the distance between π₯ and 2 on the number line? Remember: distances are positive.
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ex: What is the distance between π₯ and 2 on the number line
ex: What is the distance between π₯ and 2 on the number line? Remember: distances are positive.
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ex: What is the distance between π₯ and 2 on the number line
ex: What is the distance between π₯ and 2 on the number line? Remember: distances are positive.
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ex: What do these expressions mean on the number line? π₯β3 π₯+5 π₯
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ex: What do these expressions mean on the number line? π₯β3 π₯+5 π₯
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ex: What do these expressions mean on the number line? π₯β3 π₯+5 π₯
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ex: What do these expressions mean on the number line? π₯β3 π₯+5 π₯
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ex: What do these expressions mean on the number line? π₯β3 π₯+5 π₯
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ex: What do these expressions mean on the number line? π₯β3 π₯+5 π₯
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ex: Solve π₯β2 =7.
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ex: Solve π₯β2 =7.
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ex: Solve π₯β2 =7.
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ex: Solve π₯β2 =7.
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ex: Solve π₯β2 =7.
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ex: Solve π₯β2 =7.
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ex: Solve π₯β2 <7. Show the solutions on the number line.
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ex: Solve π₯β2 <7. Show the solutions on the number line.
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ex: Solve π₯β2 <7. Show the solutions on the number line.
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ex: Show π₯β π₯ 0 <3 on the number line ( π₯ 0 is a constant).
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ex: Show π₯β π₯ 0 <3 on the number line ( π₯ 0 is a constant).
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ex: Show π₯β π₯ 0 <3 on the number line ( π₯ 0 is a constant).
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ex: Show π₯β π₯ 0 <3 on the number line ( π₯ 0 is a constant).
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ex: Show π₯β π₯ 0 <3 on the number line ( π₯ 0 is a constant).
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ex: Show π₯β π₯ 0 <πΏ on the number line.
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ex: Show π₯β π₯ 0 <πΏ on the number line.
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ex: Show π₯β π₯ 0 <πΏ on the number line.
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ex: Show π₯β π₯ 0 <πΏ on the number line.
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ex: Show π₯β π₯ 0 <πΏ on the number line.
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Definition of Limit Let π(π₯) be defined on an open interval about π₯ 0 , except possibly at π₯ 0 itself. We say that the limit of π(π₯) as π₯ approaches π₯ 0 is the number πΏ, and we write lim π₯β π₯ 0 π(π₯) =πΏ if for every number π>0, there exists a corresponding number πΏ>0 such that for all π₯, 0< π₯β π₯ 0 <πΏ β π π₯ βπΏ <π . Note: β means βimpliesβ (think: βifβ¦thenβ)
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Definition of Limit Let π(π₯) be defined on an open interval about π₯ 0 , except possibly at π₯ 0 itself. We say that the limit of π(π₯) as π₯ approaches π₯ 0 is the number πΏ, and we write lim π₯β π₯ 0 π(π₯) =πΏ if for every number π>0, there exists a corresponding number πΏ>0 such that for all π₯, 0< π₯β π₯ 0 <πΏ β π π₯ βπΏ <π . Note: β means βimpliesβ (think: βifβ¦thenβ)
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Ex 1. Use the given graph of π to find a number πΏ such that if π₯β2 <πΏ then π π₯ β0.5 <0.25.
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Ex 1. Use the given graph of π to find a number πΏ such that if π₯β2 <πΏ then π π₯ β0.5 <0.25.
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Ex 1. Use the given graph of π to find a number πΏ such that if π₯β2 <πΏ then π π₯ β0.5 <0.25.
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Ex 1. Use the given graph of π to find a number πΏ such that if π₯β2 <πΏ then π π₯ β0.5 <0.25.
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Ex 1. Use the given graph of π to find a number πΏ such that if π₯β2 <πΏ then π π₯ β0.5 <0.25.
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Ex 1. Use the given graph of π to find a number πΏ such that if π₯β2 <πΏ then π π₯ β0.5 <0.25.
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Ex 1. Use the given graph of π to find a number πΏ such that if π₯β2 <πΏ then π π₯ β0.5 <0.25.
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Ex 1. Use the given graph of π to find a number πΏ such that if π₯β2 <πΏ then π π₯ β0.5 <0.25.
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Ex 2. For lim π₯β5 π₯β1 =2, find a πΏ>0 that works for π=1.
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Ex 2. For lim π₯β5 π₯β1 =2, find a πΏ>0 that works for π=1.
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Ex 2. For lim π₯β5 π₯β1 =2, find a πΏ>0 that works for π=1.
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Ex 2. For lim π₯β5 π₯β1 =2, find a πΏ>0 that works for π=1.
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Ex 2. For lim π₯β5 π₯β1 =2, find a πΏ>0 that works for π=1.
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Ex 3. For lim π₯ββ1 1/π₯ =β1, find a πΏ>0 that works for π=0.1.
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Ex 4. Prove that lim π₯β1 5π₯β3 =2 by using the π, πΏ definition of a limit.
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Ex 5. Prove that lim π₯β2 π(π₯) =4 by using the π, πΏ definition of a limit if π π₯ = π₯ 2 , π₯β 2 1, π₯=2
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Note: Here is some mathematical shorthand that you might see: β means βfor everyβ or βfor allβ β means βthere existsβ s.t. means βsuch thatβ.
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So, the definition of the limit can be written compactly: lim π₯β π₯ 0 π(π₯) =πΏ if βπ>0, βπΏ>0 s.t.βπ₯, 0< π₯β π₯ 0 <πΏβ π π₯ βπΏ <π
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