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What is the simplified value of 11Γ5Γ·23+22Γ6Γ·23+33Γ7Γ·23+44Γ8Γ·23+55Γ9Γ·23?
Solution: Try to find the common factor in the statement. E.g. all are divided by 23, all have factors which are multiple of 11 11Γ5Γ·23+2Γ11Γ6Γ·23+3Γ11Γ7Γ·23+4Γ11Γ8Γ·23+5Γ11Γ9Γ·23 = (5+2Γ6+3Γ7+4Γ8+5Γ9) = ( ) = (115) = ____ Answer: 55
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Joaquin and Leo walk to school from their homes every morning at the same time. They walk towards each other. Joaquinβs walking speed is 70 m per minute while that of Leo is 50 m per minute. They meet each other on time every day. One morning, Leo leaves home earlier to school. Therefore, he meets Joaquin 8 minutes earlier than usual. How many minutes earlier did Leo leave home? Solution: Let the distance between them = π meter. π= π₯ π=50π¦+(π₯β8)Γ(70+50) The total distance remains the same, which is the first y minutes, Leo walks alone, and the distance covered is 50π¦. And for the remaining (π₯β 8) minutes, Jaoquin and Leo walk toward each other, and the distance covered is (π₯β8)Γ(70+50) 50π¦+(π₯β8)Γ(70+50) = π₯ 50π¦+120π₯β960=120π₯ 50π¦=960 Answer:19 1 5
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The given figure shows a triangle ABC where AB is 5 times the length of AD, AC is 3 times the length of AE. How many times greater is the shaded part of the triangle ABC than the area of triangle ADE? Solution: Given AB = 5AD, AC = 3AE Assume area for β³π΄π·πΈ=π₯, drawing a line from B to E, we can derive the area for β³π΄π΅πΈ=5π₯ (same base [line AB]same height as β³π΄π·πΈ) Then, we can continue to derive area for β³π΄π΅πΆ=3β³π΄π΅πΈ(same base [line AC]same height as β³π΄π΅πΈ) =15π₯, Shaded area =β³π΄π΅πΆ ββ³π΄π·πΈ =15π₯ βπ₯=_____ Answer: shaded area is 14 times greater than triangle ADE
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Write down the natural numbers continuously from 1: 12345678910111213141516171819202122232425β¦.
Counting from left to right, the three 2s appear successively for the first time starting with the 34th digit. Starting with which digit will the five 2s appear successively for the first time? Solution: The five 2s appear when counting 222, then 223 β¦ β¦. β One digit: from 1 till 9, 1 x 9 = 9 digits Two digits: from 10 till 99, (99 β ) x 2 = 180 digits Three digits: from 100 till 221, (221 β ) x 3 = 366 The number 222 starts at = ___ Note: remember to add 1 Answer: 556
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