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Trig Equations
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f(x)= cos π₯ 2 , 0Β°<π₯β€360Β° g x =βtan π₯+30 , β360Β°<π₯β€0Β°
Trigonometry KUS objectives BAT rearrange and solve trig equations BAT Starter: sketch these graphs f(x)= cos π₯ 2 , Β°<π₯β€360Β° g x =βtan π₯+30 , β360Β°<π₯β€0Β° h x =β2sin π₯β90 , β180Β°<π₯β€180Β° Check using Desmos / geogebra
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Solve sin π =2 cos π in the interval 0β€ π β€360Β°
WB29 Solve sin π =2 cos π in the interval 0β€ π β€360Β° Divide by CosΞΈ Use Trig Identities Use Tan-1 2 y = TanΞΈ 90 180 270 360 63.4 243.4
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Solve π ππ 2 (πβ30) = 1 2 in the interval 0β€ π β€360Β°
WB30 solve Quadratic Equations given to you using Sin, Cos or Tan Solve π ππ 2 (πβ30) = in the interval 0β€ π β€360Β° Work out the acceptable range. Subtract 30 Square root both sides. On fractions root top and bottom separately. Can be positive or negative. 45 135 1/β2 y = SinΞΈ -1/β2 90 180 270 360 225 315 360 added to get a value in the range
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Work out what value would make either bracket 0
WB31 solve Quadratic Equations given to you using Sin, Cos or Tan Solve πππ 2 π β cos π β1 =0 in the interval 0β€ π β€360Β° Factorise Work out what value would make either bracket 0 360 1 CosΞΈ = 1 has 2 solutions y = CosΞΈ -0.5 CosΞΈ = -0.5 has 2 solutions 90 180 270 360 120 240
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Work out what value would make either bracket 0
WB32 solve Quadratic Equations given to you using Sin, Cos or Tan Solve π ππ 2 π β3 sin π +2=0 in the interval 0β€ π β€360Β° Factorise Work out what value would make either bracket 0 2 SinΞΈ = 2 has no solutions 90 1 SinΞΈ = 1 has 1 solution y = SinΞΈ 90 180 270 360
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Work out what value would make 0
WB33 solve Quadratic Equations given to you using Sin, Cos or Tan Solve π ππ 2 π + sin π =0 in the interval 0β€ π β€360Β° 3 π ππ 2 π + sin π =0 Factorise sin π 3 sin π +1 =0 Work out what value would make 0 sin π =0 or sin π = 1 3 sin π =0 gives π=90Β° sin π = gives π=19.5Β°, 160.5Β°,
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4 π ππ 2 π₯ +2=10 cos π₯ cos π₯ = 1 2 or cos π₯ =β3
WB34 exam Q Solve for 0β€ ΞΈ β€360°   all the solutions of 4 sin 2 x +2=10 cos x You must show clearly how you obtained your answers 4 π ππ 2 π₯ +2=10 cos π₯ cos π₯ = or cos π₯ =β3 4 β4 πππ 2 π₯ +2=10 cos π₯ 4 πππ 2 π₯ +10 cos π₯ β6=0 cos π₯ =β3 gives ππ π πππ’π‘ππππ 2 πππ 2 π₯ +5 cos π₯ β3=0 2 cos π₯ β1 cos π₯ +3 =0 cos π₯= gives x=60Β°, 300Β°
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π‘ππ 2 πβπ‘πππ=0, 0β€πβ€360 2sin πβπππ π=0, 0β€πβ€180
Practice 3 Solve these equations 2sin πβπππ π=0, 0β€πβ€180 π‘ππ 2 πβπ‘πππ=0, 0β€πβ€360 4 πππ 2 π+3 sin π =4, 0β€πβ€360 π ππ 2 π= , β€πβ€180
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One thing to improve is β
KUS objectives BAT rearrange and solve trig equations self-assess One thing learned is β One thing to improve is β
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