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Multivariable LINEAR systems

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Presentation on theme: "Multivariable LINEAR systems"— Presentation transcript:

1 Multivariable LINEAR systems
Ch 7.3 Multivariable LINEAR systems

2 EX 1 Solve x – 2y + 3z = 9 y + 4z = 7 z = 2

3

4 Planes!

5 The 3D world

6 EX 2 (Using Gaussian Elimination)
Solve x -2y + 3z = 9 -x + 3y + z = -2 2x -5y + 5z = 17

7 Practice!

8 Ex 3 Solving a system with infinite solutions
x + y – 3z = -1 -x + 2y = 1 y – z = 0 Let z = a Then back sub!

9 Solving non-square systems when given two equations
Step 3: Substitute z=a into the new equation “3” and solve for the remaining variable in terms of a. Step 4: Substitute z = a and the answer from step 3 into one of the original equations to get your remaining variable in terms of a. X – 2y + z = 2 2x – y – z = 1 Step 1: Let z = a Step 2: Eliminate another variable other than z from two equations. Call this equation “3”.

10 You Try! X – 3y + 2z = 18 5x – 13y +12 z = 80 Step 1: Let z = a
Step 3: Substitute z=a into the new equation “3” and solve for the remaining variable in terms of a. Step 4: Substitute z = a and the answer from step 3 into one of the original equations to get your remaining variable in terms of a. X – 3y + 2z = 18 5x – 13y +12 z = 80 Step 1: Let z = a Step 2: Eliminate another variable other than z from two equations. Call this equation “3”. (-5a+3, -a-5,a)

11 “Warm Up” Recall your knowledge of rational expressions. Add Add 2 𝑥−3 + −1 𝑥+2

12 Partial Fractions A Rational Expression can be often written as the sum of two or more simpler rational expressions. For example, 𝑥+7 𝑥 2 −𝑥 −6 = 2 𝑥−3 + −1 𝑥+2 One of the most important applications of partial fractions is in calculus “Partial Fractions”

13 EX 1” Write the partial fraction decomposition of 𝑥+7 𝑥 2 −𝑥 −6
Step 1: Factor the denominator to determine what each denominator of your partial fractions will be Step 2: Write the expression Step 4: Equate Coefficients and Solve Step 3: Multiply each side of eq. by LCD (x -3)(x+2) A + B = 1 2A – 3B = 7 A = 2 and back-sub to get B = -1 So answer is 2 𝑥−3 + −1 𝑥+2 𝑥+7 𝑥 2 −𝑥 −6 = 𝐴 𝑥−3 + 𝐵 𝑥+2 X + 7 = A (x+2) + B(x-3) = Ax + 2A + Bx -3B = (A + B)x + 2A – 3B

14 You Try! Write the partial fraction decomposition
a) 5 𝑥 2 +𝑥− b) 𝑥−2 𝑥 2 +4𝑥+3

15 EX 2: Partial Fraction Decomposition with Repeated Linear Factors
Write the partial fraction decomposition of 5 𝑥 2 +20𝑥+6 𝑥 3 +2 𝑥 2 +𝑥

16 You Try! 2𝑥−3 (𝑥−1)(𝑥−1)

17 Practice Test!


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