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Radiochemical Dating Chp 24.

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Presentation on theme: "Radiochemical Dating Chp 24."— Presentation transcript:

1 Radiochemical Dating Chp 24

2 Iceman Austria/Italy Border dated: BCE Horse Cave Painting France 13000 BCE

3 Carbon Dating-to age once living artifacts.
Constantly forming C-14 mixes with stable C-12 and C-13 in Earth's biosphere. Plants take in carbon atoms in photosynthesis and animals eat the plants. The ratio of C-14, C-12, and C-13 remains constant as long as organism is alive. After death, no more carbon is ingested and the C-14 starts to decay. C-14 has a half life of 5730 years. The ratio of unstable C-14 to stable C-12 and C-13 decreases. Scientists measure this ratio and compare it to the constant atmospheric ratio to determine the object's age. C-14 dating is limited to dating objects up to about 45,000 years.

4 Example 2 pg 872-Calculating the Amount of Remaining Isotope
Krypton-85 is used in indicator lights of appliances.The half-life of Krypton-85 is 11y. How much of a 2.00mg sample remains after 33 years?

5 Example 2 pg 872-Calculating the Amount of Remaining Isotope
Krypton-85 is used in indicator lights of appliances.The half-life of Krypton-85 is 11y. How much of a 2.00mg sample remains after 33 years? 33 yrs = 3 half lives 11 yrs 3 halfs lives = ½ x ½ x ½ = 1/8 1/8 x 2.00 mg = mg

6 The half life of cobalt-5 is 270 days. How much of a 5
The half life of cobalt-5 is 270 days. How much of a mg sample will remain after 810 days?

7 The half life of cobalt-5 is 270 days. How much of a 5
The half life of cobalt-5 is 270 days. How much of a mg sample will remain after 810 days? 810 days = 3 half lives 270 days 3 half lives = 1/8 1/8 x mg = mg

8 9. Bandages can be sterilized by exposure to gamma radiation from cobalt-60 which has a half-life of 5.27 y. How much of a 10.0 mg sample of cobalt-60 is left after 1 half life? Two half lives? Three? ½ x mg = 5.00 mg ¼ x mg = mg 1/8 x mg = 1.25 mg

9 10. If the passing of 5 half lives leaves 25 mg of a strontium-90 sample, how much was present in the beginning?

10 10. If the passing of 5 half lives leaves 25 mg of a strontium-90 sample, how much was present in the beginning? ½ x ½ x ½ x ½ x ½ = 1/32 32 x 25 mg = 800 mg


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