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26. Solving Matrix Equations

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Presentation on theme: "26. Solving Matrix Equations"— Presentation transcript:

1 26. Solving Matrix Equations

2 Solving Matrix Equations
Suppose Ax = B How do you solve for x? We cannot divide matrices, but we can multiply by the inverse. Note: Inverse must be on left side. X = A-1B

3 Solving Matrix Equations
Step 1: Find A-1 Step 2: Multiply both sides of the equation by A-1 on the left

4 Solving a Matrix Equation

5 Step 2: Multiply both sides of the equation
Step 1: Find A-1 A-1= Step 2: Multiply both sides of the equation By A-1 on the left

6 Solution by multiplying
You can check the Solution by multiplying AX to see if you get B

7 Ex. You try!! Solve

8 Example Use an inverse matrix to solve this system. x-2y=0 2x-3y = 3

9 Matrix Equations Example: Solve the system 3x - 2y = x + 2y = -5

10 Matrix Equations Example #2: Solve the 3 x 3 system 3x - 2y + z = 9 x + 2y - 2z = -5 x + y - 4z = -2 Using a graphing calculator,

11 Matrix Equations Example #2, continued

12 Word Problem Example 1 Kevin would like to buy 10 bouquets. The standard bouquet costs $7, and the deluxe bouquet costs $12. He can only afford to spend $100. How many of each type can he buy? Define Variables: X: standard bouquet Y: deluxe bouquet Equation 1 Cost: x+12y=100 Equation 2 Bouquets : x+y=10 Solution: (4,6)

13 Word Problem Example 2 A hot air balloon is 10 meters above the ground and rising at a rate of 15 meters per minute. Another balloon is 150 meters above the ground and descending at a rate of 20 meters per minute. When will the two balloons meet? Define Variables: x=minutes y=height in meters Equation 1 y=15x+10 Equation 2 y=-20x+150 Solution: (4,70)

14 Word problem Example 3 A group of 3 adults and 10 students paid $102 for a cavern tour. Another group of 3 adults and 7 students paid $84 for the tour. Find the admission price for an adult ticket and a student ticket. Define Variables: x= adult ticket price y=student ticket price Equation 1 3x+10y=102 Equation 2 3x+7y=84 Solution (14,6)

15 An Algebra Test contains 38 problems
An Algebra Test contains 38 problems. Some of the problems are worth 2 points each. The rest of the questions are worth 3 points each. A perfect score is 100 points. How many problems are worth 2 points? How many problems are worth 3 points? Define Variables: x=2 pt. questions y=3 pt. questions Equation 1 x+y=38 Equation 2 2x+3y=100 Solution (14,24)

16 Example The sum of the ages of Ryan and his father is 66. His father is 10 years more than 3 times as old as Ryan. How old are Ryan and his father? Define Variables x=Ryan’s age y=Dad’s age Equation 1 x+y=66 Equation 2 y=3x+10 Solution (14,52)

17 Assessment Does taking variables out of problems make them easier or more difficult?


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