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Modeling Landscapes - Force Balance

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Presentation on theme: "Modeling Landscapes - Force Balance"— Presentation transcript:

1 Modeling Landscapes - Force Balance
Landslides - brittle failure Debris Flows- plastic materials Rockslide spawns debris flow in British Columbia, GSC

2 FAILURE OCCURS WHEN THE STRESS ON MATERIAL EXCEEDS THE STRENGTH OF THAT MATERIAL.
A deposit at equilibrium can tell you about material strength since you can calculate driving force GRAVITY ~ shear stress ~ shear strength FRICTION AND COHESION

3 Simple Physics……vectors
DRIVING force (SHEARING STRESS) is gravity, RESISTING force is soil/rock strength/FRICTION Steep slopes give greater Driving Force (STRESS) Vectors: length=magnitude

4 FACTOR OF SAFETY Resisting force Driving force >1, slope is stable
<1 slope fails Failure driven by transient event, superimposed on geology

5 LANDSLIDES OCCUR ON A FAILURE SURFACE
LANDSLIDES OCCUR ON A FAILURE SURFACE. ALL STRENGTH ANALYSES ARE MADE IN REFERENCE TO THE FAILURE SURFACE. Translation - flat plane rotation - circular arc

6 SHEAR FORCE h IS THE THICKNESS OF THE SLAB MEASURED
PERPENDICULAR TO THE SURFACE, meters IS THE DENSITY OF THE SLAB MATERIAL, kg m-3  IS THE SLOPE ANGLE OF THE FAILURE SURFACE g IS THE ACCELERATION OF GRAVITY, 9.8 m s-2 SHEAR FORCE

7 GREATER THE NORMAL FORCE THE GREATER THE RESISTING FORCE
FRICTIONAL STRENGTH GREATER THE NORMAL FORCE THE GREATER THE RESISTING FORCE What is normal anyhow? NORMAL FORCE

8 NORMAL FORCE () h IS THE THICKNESS OF THE SLAB MEASURED
PERPENDICULAR TO THE SURFACE, meters IS THE DENSITY OF THE SLAB MATERIAL, kg m-3  IS THE SLOPE ANGLE OF THE FAILURE SURFACE g IS THE ACCELERATION OF GRAVITY, 9.8 m s-2 NORMAL FORCE ()

9 "c" COHESION IS THE TENDENCY OF A MATERIAL TO "STICK" TO ITSELF
"c" COHESION IS THE TENDENCY OF A MATERIAL TO "STICK" TO ITSELF. CLAYS ARE COHESIVE AS ARE ROCKS OR SOILS WHICH HAVE UNDERGONE SOME CEMENTATION. COHESION IS EXPRESSED IN PASCALS (kg m-1 s-2). CLAYS HAVE COHESIONS RANGING FROM TO PASCALS. TILLS HAVE COHESIONS ABOVE PASCALS. OR THE ANGLE OF INTERNAL FRICTION IS A PROPERTY OF THE MATERIAL AND RANGES FROM OVER 50o FOR COARSE GRAVEL TO LESS THAN 30o FOR FINE SAND.  IS THE NORMAL FORCE EXCERTED ON THE FAILURE SURFACE BY THE MATERIAL ABOVE IT.. THE NORMAL STRESS CAN BE EXPRESSED IN PASCALS (kg m-1 s-2)

10 How does one find parameters?
Shear stress or strength Normal Force

11 What does each parameter mean?
Hint..this is the equation of a straight line!

12 Soil Strength Parameters (Selby, 1993)

13 Strength or shear force
Normal stress (kN/m2)

14 WATER MATTERS SUBTRACTING VECTORS
FORCE BALANCE MAY TIP BOUYANCY FORCE WET NORMAL FORCE High water table (pore pressure) reduces effective normal force

15 u IS THE PRESSURE OF THE WATER AT THE FAILURE PLAIN WHICH CAN BE EXPRESSED IN PASCALS (kg m-1 s-2) USING THE EQUATION BELOW. h' IS THE ELEVATION OF THE WATER TABLE ABOVE THE FAILURE SURFACE (meters).

16 Factor of Safety Calculating Formula Includes pore pressure

17 Effective Cohesion -- Vegetation Effects
from Selby, 1993 Orgeon slide in clearcut

18 CLEARCUTTING AND LANDSLIDES
Slide scars CLEARCUTTING AND LANDSLIDES

19 100 Till 10 Sand 1 0.1 4 8 12 Factor of Safety
100 Till o (c = 150 kpa,  = 33.5 ) 10 Sand Factor of Safety o (c = 1 kpa,  = 37 ) 25o slope 1 35o slope saturated 0.75 m slab 0.1 4 8 12 Effective Root Cohesion (kPa)

20 Bishop method of slices
Rotational Failures

21 http://www. uky. edu/AS/Geology/howell/goodies/elearning/module11swf

22 What is the shear strength of debris flow material in Death Valley?
Rise/run 60’/1200’= 0.02 What is the shear strength of debris flow material in Death Valley? 2000 kg m-3 * 9.8 m s-2 * 3 m * sin   g h sin  2000 kg m-3 * 9.8 m s-2 * 3 m * 0.02 (h) Measured thickness = 3 m (measured)= 2000 kg m-3 g (given) = 9.8 m s-2 (from map) = tan -1 (0.02) = 1.15o = 1176 m-1 s-2 (pascals) = 1.2 kp


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