1. A beam of mass mb = 10.0 kg, is suspended from the ceiling by a single rope. It has a mass of m2 = 40.0 kg attached at one end and an unknown mass m1 attached at the other. The beam has a length of L = 3 m, it is in static equilibrium, and it is horizontal, as shown in the figure above. The tension in the rope is T = 637 N.
1. Determine the mass of the beam.
Mass = 15 kg
2) Determine the distance, x, from the left end of the beam to the point where the rope is attached. Note: take the torque about the left end of the beam.
To be in balance, the clockwise torques must equal the counterclockwise torques.
With the pivot at the left end of the bar:
Clockwise torques = weight of beam*L/ kg*9.81N/kg * 3 m = mN mN
= mN
Counterclockwise torques = T*X = (637 N)*X
Set the clockwise torques = counterclockwise torques and solve for X