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MOMENTUM & IMPULSE.

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Presentation on theme: "MOMENTUM & IMPULSE."— Presentation transcript:

1 MOMENTUM & IMPULSE

2 Momentum Often misused word, though most have the right idea.
4/23/2008 Momentum Often misused word, though most have the right idea. Momentum, denoted p, is mass times velocity p = m·v Momentum is a conserved quantity (and a vector) Often relevant in collisions (watch out for linebackers!) News headline: Snowball Hits Unsuspecting Sled 1 kg snowball strikes 5 kg sled at 12 m/s and sticks Momentum before collision: (1 kg)(12 m/s) = 12 kg*m/s Lecture 9

3 Bowling ball or basketball?
Picture two lanes at a bowling alley, one with a bowling ball the other with a basketball going at the same speed. Which will exert more force on the pins? Why?

4 Example A 2250 kg pickup truck has a velocity of 25 m/s to the east. What is the momentum of the truck?

5 Solution p = mv (2250 kg)(25 m/s east) 5.6 x 104 kg x m/s to the east

6 PRACTICE A 21 kg child on a 5.9 kg bike is riding with a velocity of 4.5 m/s to the northwest. What is the total momentum of the child and the bike together? What is the momentum of the child? What is the momentum of the bike?

7 LINEAR MOMENTUM Impulse F∆t = ∆p = mv – mu
The product of the force and the time of a collision The impulse-momentum theorem states that when a net force is applied to an object over a certain time interval, the force will cause a change in the object’s momentum [ F∆t = m∆v ] F∆t = ∆p = mv – mu

8 LINEAR MOMENTUM Stopping times and distances depend on the impulse-momentum theorem. Force is reduced when the time interval of an impact is increased.

9 EXAMPLE A 57 gram tennis ball falls on a tile floor. The ball changes velocity from -1.2 m/s to +1.2 m/s in 0.02 s. What is the average force on the ball?

10 SOLUTION using FΔt= mΔv F x (0.02 s) = (0.057 kg)(2.4 m/s) F= 6.8 N

11 PRACTICE 2 An 82 kg man drops from rest on a diving board 3.0 m above the surface of the water and comes to rest 0.55 s after reaching the water. What is the net force on the diver as he is brought to rest?

12 PRACTICE 3 A 2240 kg car traveling to the west slows down uniformly from m/s to 5.00 m/s. How long does it take the car to decelerate if the force on the car is 8410 N to the east? How far does the car travel during deceleration?

13 Solution ∆t = ∆p / F ∆t = mv – mu / F Givens: Mass = 2240 kg
u = 20.0 m/s to the west = m/s v = 5.00 m/s to the west = m/s F = 8410 N to the east Equation to use: F∆t = ∆p ∆t = ∆p / F ∆t = mv – mu / F

14 CAR CRASH Would you rather be in a head on collision with an identical car, traveling at the same speed as you, or a brick wall? Assume in both situations you come to a complete stop.

15 CAR CRASH Everyone should vote now
Raise one finger if you think it is better to hit another car, two if it’s better to hit a wall and three if it doesn't’t matter.

16 CAR CRASH The answer is… It doesn’t matter! Look at FΔt= mΔv
In both situations, Δt, m, and Δv are the same! The time it takes you to stop depends on your car, m is the mass of your car, and Δv depends on how fast you were initially traveling.

17 DISCUSSION Force is reduced when the time interval of an impact is increased. Imagine a person being tossed in the air and caught in a blanket. The blanket “gives way” and extends the time of collision to change the momentum over a longer period of time.

18 TASK Using concepts we’ve covered, explain what is happening in the following graphic.


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