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Electricity and Magnetism
Physics 208 Dr. Tatiana Erukhimova Lecture 11
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Gauss’s Law The total flux of electric field out of any closed surface is equal to the charge contained inside the surface divided by
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The flux of
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Electric flux through a sphere
A positive point charge q=3.0 C is surrounded by a sphere with radius 0.2 m centered on the charge. Find the electric flux through the sphere due to this charge.
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S Definition of a solid angle does not depend on radius The largest
Then
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Proof of Gauss’s Law
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Electric field of a single fixed charge
Chasing the tail: Electric field of a single fixed charge
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Conductors and insulators
Charges reside at the surface of the conductor + + + + + + + + Conductor + + E=0 + + + + +
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Have a great day! Hw: All Chapter 4 problems and exercises
Reading: Chapter 4
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