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Stekolnikova Daria Voronezh - 2

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1 Stekolnikova Daria Voronezh - 2
Problem 5 Falling ball Stekolnikova Daria Voronezh - 2

2 Condition of the problem
An electronic balance (1) is connected to a PC (5) in order to record the time dependence of the measured weight. A light frame (4) is mounted on a tall beaker (2) filled with water. The frame has a holder (3) allowing controlled release of a small ball such that it falls into the water. The beaker is placed on the balance as depicted in the Figure. Investigate how the readings of the balance reflect the different phases of the motion of the ball.

3 Balance - device that measure weight.
F T T T mg mg mg P = mg T = P = mg P = T = mg - F

4 Our setting Dynamometer Holder with the ball Ruler Beaker PC

5 Model Fixed on the foundation ball Vessel with water

6 Explanation of the process
P โ€“ shows with which force the ball affects on the system T ๐‘ƒ= ๐น ๐‘”๐‘Ÿ ๐น ๐‘”๐‘Ÿ

7 ๐น ๐‘”๐‘Ÿ ๐‘ƒ=0

8 ๐‘ƒ= ๐น ๐‘”๐‘Ÿ โˆ’ ๐น ๐‘ค๐‘Ÿ ๐น ๐‘ค๐‘Ÿ ๐น ๐‘ค๐‘Ÿ ๐น ๐‘”๐‘Ÿ

9 ๐‘ƒ= ๐น ๐‘”๐‘Ÿ โˆ’ ๐น ๐ด โˆ’ ๐น ๐‘Ÿ๐‘“ ๐น ๐‘Ÿ๐‘“ ๐น ๐ด ๐น ๐‘”๐‘Ÿ

10 ๐‘ƒ= ๐น ๐‘”๐‘Ÿ โˆ’ ๐น ๐ด โˆ’ ๐น ๐‘Ÿ๐‘“ ๐น ๐‘Ÿ๐‘“ ๐น ๐ด ๐น ๐‘”๐‘Ÿ

11 Hypothesis โˆ†๐‘ƒโˆผโˆ†๐‘Ž

12 ๐น ๐‘”๐‘Ÿ ๐น ๐‘ ๐‘ก ๐น ๐‘”๐‘Ÿ ๐น ๐‘Ÿ๐‘“ ๐น ๐ด ๐น =๐‘š ๐‘Ž โˆ†๐‘ƒ=๐‘šโˆ†๐‘Ž โˆ†๐‘Ž

13 Results โˆ†๐‘ƒโ‰ˆ0,2๐‘

14 ๐‘š ๐‘ ๐‘’๐‘ก = 99,85 ๐‘”๐‘Ÿ ๐‘š ๐‘ = 31,15 ๐‘”๐‘Ÿ ๐‘š ๐‘ค = 240 ๐‘”๐‘Ÿ

15 ๐‘ = 0,137 ๐‘š

16 โˆ†๐‘กโ‰ˆ ๐‘ 

17 ๐‘š ๐‘ โˆ™ ๐‘ฃ ๐‘ =( ๐‘š ๐‘ + ๐‘š ๐‘ ๐‘’๐‘ก + ๐‘š ๐‘ค )โˆ™ ๐‘ฃ ๐‘ ๐‘–๐‘ 
Calculations ๐‘š ๐‘ โˆ™ ๐‘ฃ ๐‘ =( ๐‘š ๐‘ + ๐‘š ๐‘ ๐‘’๐‘ก + ๐‘š ๐‘ค )โˆ™ ๐‘ฃ ๐‘ ๐‘–๐‘  ๐‘ = ๐‘ฃ ๐‘ 2 2๐‘” ๐‘š ๐‘ ๐‘–๐‘  = 0,371 ๐‘˜๐‘” ๐‘ฃ ๐‘ = 2๐‘”๐‘  ๐‘ฃ ๐‘ =1,63 ๐‘š ๐‘ 

18 ๐‘ฃ ๐‘ ๐‘–๐‘  = ๐‘š ๐‘ โˆ™ ๐‘ฃ ๐‘ ๐‘š ๐‘ ๐‘–๐‘  ๐‘ฃ ๐‘ ๐‘–๐‘  =0,137 ๐‘š ๐‘  ๐‘Ž ๐‘ ๐‘–๐‘  = ๐‘ฃ ๐‘ ๐‘–๐‘  โˆ†๐‘ก ๐‘Ž ๐‘ ๐‘–๐‘  =0,416 ๐‘š ๐‘  2

19 โˆ†๐‘ƒ=๐‘šโˆ†๐‘Ž โˆ†๐‘ƒ= ๐‘š ๐‘ ๐‘–๐‘  โˆ™ ๐‘Ž ๐‘ ๐‘–๐‘  โˆ†๐‘ƒ= 0,371 ๐‘˜๐‘” โˆ™0,416 ๐‘š ๐‘  2 =๐ŸŽ,๐Ÿ๐Ÿ“๐Ÿ’๐‘ต

20 Comparing results Experimental โˆ†๐‘ƒ=0,2๐‘ Theoretically โˆ†๐‘ƒ=0,15๐‘
Error: 0,05N โ€“ normal error for such experiments Our hypothesis was successfully confirmed!

21 During the traffic the weight of the whole system changes:
Conclusion During the traffic the weight of the whole system changes: 1. ๐‘ก=๐‘œ โŸถ ๐‘ƒ 0 = ๐‘ƒ ๐‘ ๐‘–๐‘  + ๐‘ƒ ๐‘ 2. ๐‘‡โ„Ž๐‘’ ๐‘š๐‘œ๐‘š๐‘’๐‘›๐‘ก ๐‘œ๐‘“ ๐‘“๐‘Ž๐‘™๐‘™๐‘–๐‘›๐‘” โŸถ ๐‘ƒ 1 = ๐‘ƒ ๐‘ ๐‘–๐‘  3. ๐‘‡โ„Ž๐‘’ ๐‘š๐‘œ๐‘š๐‘’๐‘›๐‘ก ๐‘œ๐‘“ ๐‘๐‘œ๐‘›๐‘ก๐‘Ž๐‘๐‘ก ๐‘ค๐‘–๐‘กโ„Ž ๐‘ค๐‘Ž๐‘ก๐‘’๐‘ŸโŸถ ๐‘ƒ 2 = ๐‘ƒ ๐‘ ๐‘–๐‘  +๐‘šโˆ†๐‘Ž 4. ๐‘‡โ„Ž๐‘’ ๐‘’๐‘›๐‘‘โŸถ ๐‘ƒ 3 = ๐‘ƒ 0

22 Thank you for your attention!


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