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Five-Minute Check (over Lesson 6–3) CCSS Then/Now New Vocabulary
Key Concept: Definition of nth Root Key Concept: Real nth Roots Example 1: Find Roots Example 2: Simplify Using Absolute Value Example 3: Real-World Example: Approximate Radicals Lesson Menu
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A. B. C. D. D = {x | x ≤ –2}, R = {y | y ≥ 0} 5-Minute Check 1
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A. B. C. D. D = {x | x ≤ –2}, R = {y | y ≥ 0} 5-Minute Check 1
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A. B. C. D. 5-Minute Check 2
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A. B. C. D. 5-Minute Check 2
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A. B. C. D. 5-Minute Check 3
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A. B. C. D. 5-Minute Check 3
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A. B. C. D. 5-Minute Check 4
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A. B. C. D. 5-Minute Check 4
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C. D. A. B. 5-Minute Check 5
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C. D. A. B. 5-Minute Check 5
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The point (3, 6) lies on the graph of Which ordered pair lies on the graph of
B. C. (2, –2) D. (–2, 2) 5-Minute Check 6
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The point (3, 6) lies on the graph of Which ordered pair lies on the graph of
B. C. (2, –2) D. (–2, 2) 5-Minute Check 6
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Mathematical Practices 6 Attend to precision.
Content Standards A.SSE.2 Use the structure of an expression to identify ways to rewrite it. Mathematical Practices 6 Attend to precision. CCSS
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You worked with square root functions.
Simplify radicals. Use a calculator to approximate radicals. Then/Now
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nth root radical sign index radicand principal root Vocabulary
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Concept
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Concept
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Find Roots = ±4x4 Answer: Example 1
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Answer: The square roots of 16x8 are ±4x4.
Find Roots = ±4x4 Answer: The square roots of 16x8 are ±4x4. Example 1
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Find Roots Answer: Example 1
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Find Roots Answer: The opposite of the principal square root of (q3 + 5)4 is –(q3 + 5)2. Example 1
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Find Roots Answer: Example 1
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Find Roots Answer: Example 1
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Find Roots Answer: Example 1
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Find Roots Answer: Example 1
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A. Simplify A. ±3x6 B. ±3x4 C. 3x4 D. ±3x2 Example 1
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A. Simplify A. ±3x6 B. ±3x4 C. 3x4 D. ±3x2 Example 1
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B. Simplify . A. –(a3 + 2)4 B. –(a3 + 2)8 C. (a3 + 2)4 D. (a + 2)4
Example 1
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B. Simplify . A. –(a3 + 2)4 B. –(a3 + 2)8 C. (a3 + 2)4 D. (a + 2)4
Example 1
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C. Simplify A. 2xy2 B. ±2xy2 C. 2y5 D. 2xy Example 1
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C. Simplify A. 2xy2 B. ±2xy2 C. 2y5 D. 2xy Example 1
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Simplify Using Absolute Value
Note that t is a sixth root of t 6. The index is even, so the principal root is nonnegative. Since t could be negative, you must take the absolute value of t to identify the principal root. Answer: Example 2
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Simplify Using Absolute Value
Note that t is a sixth root of t 6. The index is even, so the principal root is nonnegative. Since t could be negative, you must take the absolute value of t to identify the principal root. Answer: Example 2
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Since the index is odd, you do not need absolute value.
Simplify Using Absolute Value Since the index is odd, you do not need absolute value. Answer: Example 2
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Since the index is odd, you do not need absolute value.
Simplify Using Absolute Value Since the index is odd, you do not need absolute value. Answer: Example 2
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A. Simplify A. x B. –x C. |x| D. 1 Example 2
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A. Simplify A. x B. –x C. |x| D. 1 Example 2
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B. Simplify . A. |3(x + 2)3| B. 3(x + 2)3 C. |3(x + 2)6| D. 3(x + 2)6
Example 2
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B. Simplify . A. |3(x + 2)3| B. 3(x + 2)3 C. |3(x + 2)6| D. 3(x + 2)6
Example 2
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Understand You are given the value for k.
Approximate Radicals A. SPACE Designers must create satellites that can resist damage from being struck by small particles of dust and rocks. A study showed that the diameter in millimeters d of the hole created in a solar cell by a dust particle traveling with energy k in joules is about Estimate the diameter of a hole created by a particle traveling with energy 3.5 joules. Understand You are given the value for k. Plan Substitute the value for k into the formula. Use a calculator to evaluate. Example 3A
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Solve Original formula
Approximate Radicals Solve Original formula k = 3.5 Use a calculator. Answer: Example 3A
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Solve Original formula
Approximate Radicals Solve Original formula k = 3.5 Use a calculator. Answer: The hole created by a particle traveling with energy of 3.5 joules will have a diameter of approximately millimeters. Example 3A
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Check Original equation
Approximate Radicals Check Original equation Add to each side. Divide both sides by Cube both sides. Simplify. Example 3A
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Approximate Radicals B. SPACE Designers must create satellites that can resist damage from being struck by small particles of dust and rocks. A study showed that the diameter in millimeters d of the hole created in a solar cell by a dust particle traveling with energy k in joules is about If a hole has diameter of 2.5 millimeters, estimate the energy with which the particle that made the hole was traveling. Example 3B
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Solve Original formula
Approximate Radicals Solve Original formula d = 2.5 Use a calculator. Answer: Example 3B
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Solve Original formula
Approximate Radicals Solve Original formula d = 2.5 Use a calculator. Answer: The hole with a diameter of 2.5 millimeters was created by a particle traveling with energy of 23.9 joules. Example 3B
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A. PHYSICS The time T in seconds that it takes a pendulum to make a complete swing back and forth is given by the formula where L is the length of the pendulum in feet and g is the acceleration due to gravity, 32 feet per second squared. Find the value of T for a 2-foot-long pendulum. A. about 0.25 second B. about 1.57 seconds C. about seconds D. about seconds Example 3A
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A. PHYSICS The time T in seconds that it takes a pendulum to make a complete swing back and forth is given by the formula where L is the length of the pendulum in feet and g is the acceleration due to gravity, 32 feet per second squared. Find the value of T for a 2-foot-long pendulum. A. about 0.25 second B. about 1.57 seconds C. about seconds D. about seconds Example 3A
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B. PHYSICS The time T in seconds that it takes a pendulum to make a complete swing back and forth is given by the formula where L is the length of the pendulum in feet and g is the acceleration due to gravity, 32 feet per second squared. How long is the pendulum if it takes 5 seconds to swing back and forth? A. about 2.5 feet B. about 10 feet C. about 20.3 feet D. about 25.5 feet Example 3B
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B. PHYSICS The time T in seconds that it takes a pendulum to make a complete swing back and forth is given by the formula where L is the length of the pendulum in feet and g is the acceleration due to gravity, 32 feet per second squared. How long is the pendulum if it takes 5 seconds to swing back and forth? A. about 2.5 feet B. about 10 feet C. about 20.3 feet D. about 25.5 feet Example 3B
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End of the Lesson
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