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One-Way ANOVA ANOVA = Analysis of Variance
This is a technique used to analyze the results of an experiment when you have more than two groups
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Example You measure the number of days 7 psychology majors, 7 sociology majors, and 7 biology majors are absent from class You wonder if the average number of days each of these three groups was absent is significantly different from one another
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Results X = 3.00 X = 2.00 X = 1.00
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Hypothesis Alternative hypothesis (H1)
H1: The three population means are not all equal
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Hypothesis Null hypothesis (H0) psych = socio = bio
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Between and Within Group Variability
Two types of variability Between the differences between the mean scores of the three groups The more different these means are, the more variability!
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Results X = 3.00 X = 2.00 X = 1.00
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Between Variability S2 = .66 X = 3.00 X = 2.00 X = 1.00
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Between Group Variability
What causes this variability to increase? 1) Effect of the variable (college major) 2) Sampling error
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Between and Within Group Variability
Two types of variability Within the variability of the scores within each group
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Results X = 3.00 X = 2.00 X = 1.00
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Within Variability S2 =.57 S2 =1.43 S2 =.57 X = 3.00 X = 2.00 X = 1.00
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Within Group Variability
What causes this variability to increase? 1) Sampling error
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Between and Within Group Variability
Between-group variability Within-group variability
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Between and Within Group Variability
sampling error + effect of variable sampling error
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Between and Within Group Variability
sampling error + effect of variable sampling error Thus, if null hypothesis was true this would result in a value of 1.00
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Between and Within Group Variability
sampling error + effect of variable sampling error Thus, if null hypothesis was not true this value would be greater than 1.00
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Calculating this Variance Ratio
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Calculating this Variance Ratio
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Calculating this Variance Ratio
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Degrees of Freedom dfbetween dfwithin dftotal
dftotal = dfbetween + dfwithin
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Degrees of Freedom dfbetween = k - 1 (k = number of groups)
dfwithin = N - k (N = total number of observations) dftotal = N - 1 dftotal = dfbetween + dfwithin
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Degrees of Freedom dfbetween = k - 1 3 - 1 = 2
dfwithin = N - k = 18 dftotal = N = 20 20 =
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Sum of Squares SSBetween SSWithin SStotal
SStotal = SSBetween + SSWithin
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Sum of Squares SStotal
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Sum of Squares SSWithin
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Sum of Squares SSBetween
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Sum of Squares Ingredients: X X2 Tj2 N n
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To Calculate the SS
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X Xs = 21 Xp = 14 XB = 7
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X X = 42 Xs = 21 Xp = 14 XB = 7
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X2 X = 42 Xs = 21 Xp = 14 XB = 7 X2s = 67 X2P = 38 X2B = 11
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X2 X = 42 X2 = 116 Xs = 21 Xp = 14 XB = 7 X2s = 67 X2P = 38
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T2 = (X)2 for each group X = 42 X2 = 116 Xs = 21 Xp = 14 XB = 7
T2P = 196 T2B = 49 T2s = 441
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Tj2 X = 42 X2 = 116 Tj2 = 686 Xs = 21 Xp = 14 XB = 7 X2s = 67
T2P = 196 T2B = 49 T2s = 441
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N X = 42 X2 = 116 Tj2 = 686 N = 21 Xs = 21 Xp = 14 XB = 7
T2P = 196 T2B = 49 T2s = 441
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n X = 42 X2 = 116 Tj2 = 686 N = 21 n = 7 Xs = 21 Xp = 14 XB = 7
T2P = 196 T2B = 49 T2s = 441
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X = 42 X2 = 116 Tj2 = 686 N = 21 n = 7 Ingredients
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X = 42 X2 = 116 Tj2 = 686 N = 21 n = 7 Calculate SS SStotal
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Calculate SS 42 32 116 21 SStotal X = 42 X2 = 116 Tj2 = 686 N = 21
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X = 42 X2 = 116 Tj2 = 686 N = 21 n = 7 Calculate SS SSWithin
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Calculate SS 686 18 116 7 SSWithin X = 42 X2 = 116 Tj2 = 686 N = 21
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X = 42 X2 = 116 Tj2 = 686 N = 21 n = 7 Calculate SS SSBetween
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Calculate SS 14 686 42 7 21 SSBetween X = 42 X2 = 116 Tj2 = 686
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Sum of Squares SSBetween SSWithin SStotal
SStotal = SSBetween + SSWithin
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Sum of Squares SSBetween = 14 SSWithin = 18 SStotal = 32 32 =
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Calculating the F value
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Calculating the F value
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Calculating the F value
14 7 2
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Calculating the F value
7
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Calculating the F value
7 18 1 18
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Calculating the F value
7 7 1
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How to write it out
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Significance Is an F value of 7.0 significant at the .05 level?
To find out you need to know both df
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Degrees of Freedom Dfbetween = k - 1 (k = number of groups)
dfwithin = N - k (N = total number of observations)
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Degrees of Freedom dfbetween = k - 1 3 - 1 = 2
dfwithin = N - k = 18 Page 394 Table F dfbetween are in the numerator dfwithin are in the denominator Write this in the table
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Critical F Value F(2,18) = 3.55 The nice thing about the F distribution is that everything is a one-tailed test
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Decision Thus, if F value > than F critical
Reject H0, and accept H1 If F value < or = to F critical Fail to reject H0
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Current Example F value = 7.00 F critical = 3.55
Thus, reject H0, and accept H1
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Alternative hypothesis (H1)
H1: The three population means are not all equal In other words, psychology, sociology, and biology majors do not have equal class attendence Notice: It does not say where this difference is at!!
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How to write it out
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