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Honors Precalculus 4/24/18 IDs on and showing.
Check-in Direction Angle and Components. Questions on Direction Angles and Components. Complete Combinations of Vectors and Resultant Vectors.
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Section 6.1 Combination of Vectors Resultant Vectors
Honors PreCalculus Section 6.1 Combination of Vectors Resultant Vectors
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Example 1: A boat is traveling due West at a speed
of 20 mph. There is an 8 mph current flowing at a bearing of 60º. What is the “true” speed of the boat? N Step 1: Resolve each vector into its components 60º 8mph 20 mph
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Example 1: A boat is traveling due West at a speed
of 20 mph. There is an 8 mph current flowing at a bearing of 60º. What is the “true” speed of the boat? N Step 2: Add horizontal components; Add vertical components. In other words; add the vectors 8mph 20 mph So, the boat’s “true” speed due West is mph. Without compensating for the current (by steering into it), it’s traveling 4 mph North.
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Example 1: A boat is traveling due West at a speed
of 20 mph. There is an 8 mph current flowing at a bearing of 60º. What is the “true” speed of the boat? N The resultant vector shows the actual direction of the boat, without compensating for the current
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Example 2: An airplane is flying 350 mph at a bearing of 132º.
If the wind is blowing 47 mph at a bearing of 300º, find: the actual (“ground”) speed of the plane and the bearing of the plane as a result of the wind N 150º 47 132º 318º 300º 350
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Example 2: An airplane is flying 350 mph at a bearing of 132º.
If the wind is blowing 47 mph at a bearing of 300º, find: the actual (“ground”) speed of the plane and the bearing of the plane as a result of the wind N 150º 47 318º 350
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Example 2: An airplane is flying 350 mph at a bearing of 132º.
If the wind is blowing 47 mph at a bearing of 300º, find: the actual (“ground”) speed of the plane and the bearing of the plane as a result of the wind N a) “ground” speed of the plane is the magnitude of the resultant vector b) Direction angle of resultant vector Bearing:
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Example 3: Three forces all work on the same object.
Force 1 = 100 lb at an angle of 50º Force 2 = 50 lb at an angle of 160º Force 3 = 80 lb at an angle of -20º Find the resultant force, and the angle at which it acts. N 100 160º 50º 50 -20º 80
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