Presentation is loading. Please wait.

Presentation is loading. Please wait.

Day 136 – Common Factors.

Similar presentations


Presentation on theme: "Day 136 – Common Factors."β€” Presentation transcript:

1 Day 136 – Common Factors

2 Factor each polynomial. a)πŸ“π’‚π’Žβˆ’πŸ“π’‚π’ b)πŸ“ 𝒙 πŸ‘ βˆ’πŸ‘ π’š 𝟐 c)𝟐 𝒄 πŸ’ βˆ’πŸ’ 𝒄 πŸ‘ +πŸ” 𝒄 𝟐
Example 1 Factor each polynomial. a)πŸ“π’‚π’Žβˆ’πŸ“π’‚π’ b)πŸ“ 𝒙 πŸ‘ βˆ’πŸ‘ π’š 𝟐 c)𝟐 𝒄 πŸ’ βˆ’πŸ’ 𝒄 πŸ‘ +πŸ” 𝒄 𝟐

3 Answer Factor the greatest common factor, or GCF, from each term a) The GCF is 5a. 5π‘Žπ‘šβˆ’5π‘Žπ‘›=5π‘Ž(π‘šβˆ’π‘›) b) The GCF is 1. 5 π‘₯ 3 βˆ’3 𝑦 2 is prime. c) The GCF is 2 𝑐 𝑐 4 βˆ’4 𝑐 3 +6 𝑐 2 =2 𝑐 2 ( 𝑐 2 βˆ’2𝑐+3) To check each factorization, multiply the two factors to find the original expression. Substitute numbers for the variables in the previous example and simplify. Compare the results. What do you find? The results are the same.

4 Example 2 Factor π‘Ÿ 𝑑+1 +π‘₯(𝑑+1).

5 Answer Notice that π‘Ÿ 𝑑+1 +𝑠 𝑑+1 contains the common binomial factor 𝑑+1. Think of 𝑑+1 as c. The expression can also be factored mentally if you apply the Distributive Property. π‘Ÿ 𝑑+1 +𝑠 𝑑+1 =(π‘Ÿ+𝑠)(𝑑+1)

6 Answer You can visualize this factoring procedure with an area model.
𝑑+1 𝑑+1 𝑑+1 π‘Ÿ π‘Ÿ + 𝑠 = + 𝑠 π‘Ÿ(𝑑+1) + 𝑠(𝑑+1) = (π‘Ÿ+𝑠)(𝑑+1)

7 Factor π‘₯ 2 +π‘₯+2π‘₯+2 by grouping.
Example 3 Factor π‘₯ 2 +π‘₯+2π‘₯+2 by grouping.

8 Answer There are several way to factor this expression by grouping. One way is to group the terms that have a common coefficient or variable. Treat π‘₯ 2 +π‘₯ as one expression, and treat 2π‘₯+2 as another expression. To check, multiply the factors.


Download ppt "Day 136 – Common Factors."

Similar presentations


Ads by Google