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Here’s a general strategy for determining empirical formulas.

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Presentation on theme: "Here’s a general strategy for determining empirical formulas."— Presentation transcript:

1 Here’s a general strategy for determining empirical formulas.
QUESTION: A sample of a compound contains g Fe and g O. What is the empirical formula of the compound? A. FeO, B. FeO2, C. Fe2O3, D. Fe3O4 General strategy: determine count-to-count (or mole-to-mole) ratio; reduce ratio to small whole numbers (first divide all counts by the smallest count; then, if necessary, find smallest multiplier to make all numbers very close to whole numbers) A sample of a compound contains g Fe and g O. What is the empirical formula of the compound? A. FeO, B. FeO2, C. Fe2O3, D. Fe3O4 PAUSE CLICK Here’s a general strategy for determining empirical formulas. You can determine empirical formulas if you have enough information to determine the relative numbers of the atoms of different elements in the compound. In other words, if you can get a count-to-count ratio for the atoms of the elements in the compound. Remember that moles are just group counts, so you can also use mole-to-mole ratio. Once you have determined the mole-to-mole ratio, all you have to do is to reduce the ratio to a small whole number ratio. Since we’re given masses in this question.... the first thing we need to do is convert them to moles By now you should know how to do this. Here’s a quick review We start with known masses of iron and oxygen then multiply CLICK CLICK by a conversion factor based on the molar mass CLICK CLICK CLICK CLICK CLICK CLICK 55.85 grams per mole is the molar mass of iron and 16.00 grams per mole is the molar mass of oxygen These calculations give us... moles of iron CLICK and moles of oxygen CONTINUED ON NEXT SLIDE 1 mol Fe 19.27 g Fe x = mol Fe 55.85 g Fe 1 mol O 7.360 g O x = mol O 16.00 g O

2 So, the iron-to-oxygen mole ratio is 0.3450 to 0.4600.
QUESTION: A sample of a compound contains g Fe and mol O. What is the empirical formula of the compound? A. FeO, B. FeO2, C. Fe2O3, D. Fe3O4 General strategy: determine count-to-count (or mole-to-mole) ratio; reduce ratio to small whole numbers (first divide all counts by the smallest count; then, if necessary, find smallest multiplier to make all numbers very close to whole numbers) So far, we have determined that the sample contained moles of iron HIGHLIGHT in table and moles of oxygen HIGHLIGHT in table So, the iron-to-oxygen mole ratio is to A good strategy for reducing this ratio to a whole number ratio is to first divide both numbers by the smaller number. HIGHLIGHT “first divide all counts by the smallest count” In this case, is the smaller number. Dividing by gives us 1.000 HIGHLIGHT 1.000 and dividing by gives us HIGHLIGHT 1.333 Note that we’re keeping four significant figures in the result because our original numbers have four significant figures. When the decimal part is at least 0.1 away from a whole number, you should not just round it off. We should not just round off to a whole number. What we need to do at this point is find the smallest whole number multiplier that will make all the numbers close to a whole number. HIGHLIGHT “if necessary, find smallest multiplier to make all numbers very close to whole number” Try 2. If that doesn’t work. Try 3, and then 4, and so on.... OK. Let’s try multiplying both numbers by 2 1.000 times 2 equals 2.000 CLICK and 1.333 times 2 equals 2.666 2.666 is still too far from a whole number. So let’s try multiplying the numbers by 3. 1.000 times 3 equals 3.000 and times 3 equals 3.999 CLICK Now, we have two numbers that are very close to whole numbers is essentially equal to 4. Therefore, the iron-to-oxygen ratio is “3 is to 4” The empirical formula is Fe3O4. The correct answer is choice D. CLICK PAUSE END RECORDING Iron Oxygen mol mol 1.000 1.333 2.000 2.666 3.000 3.999

3 Video ID: © 2008, Project VALUE (Video Assessment Library for Undergraduate Education), Department of Physical Sciences Nicholls State University Author: Glenn V. Lo Narrator: Funded by Louisiana Board of Regents Contract No. LA-DL-SELECT-13-07/08


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