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Warm Up #30: Solve by substitution
(1) y = 2x + 7 2y – 5x = 11 x = 3y – 4 2x – y = 7 (2) x + 2y = 10 3x + 4y = 8 -3x + y = 5
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8.3 The Addition Method Objective:
To solve a system of equations by using the addition method
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The Addition Method Write the second equation below the first.
Add the equations together and solve for the remaining variable. Substitute that value into either of the original equations and solve the second variable. Used when the addition will remove one of the variables.
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Solve: + x + y = 5 x - y = 1 x - y = 1 x - y = 1 x - y = 1 x - y = 1
= 6 x = 3 3 + y = 5 y = 2 (3,2)
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x + y = 5 x + y = 5 2x - y = 4 3x = 9 x = 3 3 + y = 5 y = 2 (3,2)
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2 Special Cases No solution Case 1: NO SOLUTION
Both variables cancel out but the constant does not Leaving a false equation. 4x - 2y = 2 -4x + 2y = -16 0 + 0 = -14 No solution
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Case 2: INFINITELY MANY SOLUTIONS
Both variables and the constant cancel out Leaving a true equation 5x - 7y = 6 -5x + 7y = -6 0 + 0 = 0 Infinitely many solutions
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They all do not cancel out so easily
If the equations do not eliminate a variable when you add them together: Multiply the whole equation by a number that will help you cancel it out. (multiply every term in the equation by that number)
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2 4x - 2y = 7 4x - 2y = 7 3x + y = 4 6x + 2y = 8 10x = 15 x = 1.5
(1.5,-0.5)
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-1 2x + 3y = 8 2x + 3y = 8 x + 3y = 7 -x - 3y = -7 x = 1 2(1) + 3y = 8
(1,2)
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3 4 4x + 2y = 18 12x + 6y = 54 -3x + 5y = 6 -12x + 20y = 24 26y = 78
(3,3) y = 3
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3 -5 5x + 3y = 2 15x + 9y = 6 -15x - 35y = 20 3x + 7y = -4 -26y = 26
(1,-1) x = 1
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The sum of two numbers is 72. The difference is 58. Find the numbers.
x + y = 72 x - y = 58 7 and 65
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The sum of the length and width of a rectangle is 25 cm
The sum of the length and width of a rectangle is 25 cm. The length is 2 less than twice the width. Find the length and width.
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Assignment: Page 371 (10-32) even
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