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lnkc-lnk= -[Eac/RT + lnA] - [-Ea/RT + lnA] ln(kc/k)= Ea-Eac/RT

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Presentation on theme: "lnkc-lnk= -[Eac/RT + lnA] - [-Ea/RT + lnA] ln(kc/k)= Ea-Eac/RT"— Presentation transcript:

1 lnkc-lnk= -[Eac/RT + lnA] - [-Ea/RT + lnA] ln(kc/k)= Ea-Eac/RT
CH 14 #79-a SAME FOR BOTH THEREFORE DROPS OUT. k=-Ea/RT + lnA Kc IS CATALIZED RATE CONSTANT, Eac IS CATALZED ACTIVATION ENERGY. lnkc-lnk= -[Eac/RT + lnA] - [-Ea/RT + lnA] ln(kc/k)= Ea-Eac/RT ln(kc/k)= 95.5 kJmol-55 kJ/mol/[(8.314J/K*mol)(298K)(1 kJ/1000J)] (kc/k)=1 x 107

2 lnkc-lnk= -[Eac/RT + lnA] - [-Eac/RT + lnA] ln(kc/k)= Ea-Eac/RT
CH 14 #79-a A IS SAME FOR BOTH THEREFORE DROPS OUT. k=-Ea/RT + lnA Kc IS CATALIZED RATE CONSTANT, Eac IS CATALZED ACTIVATION ENERGY. lnkc-lnk= -[Eac/RT + lnA] - [-Eac/RT + lnA] ln(kc/k)= Ea-Eac/RT ln(kc/k)= 95.5 kJmol-55 kJ/mol/[(8.314J/K*mol)(398K)(1 kJ/1000J)] (kc/k)=2 x 105

3 2[NO2(g) + SO2 (g)  NO(g) + SO3 (g) ]
CH 14 #71- 2[NO2(g) + SO2 (g)  NO(g) + SO3 (g) ] 2 NO(g) + O2 (g) 2 NO2 (g) 2SO2 (g) + O2 (g)  2 SO3 (g) WHERE NO2 IS A CATALYST, IT IS IN THE GAS STATE AS ALL OTHER SPECIES, THEREFORE IT IS A HOMOGENOUS CATALYST.

4 SLOW CH 14 #65 H2(g) + ICl (g)  HI (g) + HCl (g)
Rate = k[H2][ICl] SLOW H2(g) + ICl (g)  HI (g) + HCl (g) HI(g) + ICl(g) I2 (g) + HCl (g) H2(g) + 2 ICl(g)  I2 (g) + 2HCl (g) RATE = k[H2][HCl] Rate = k[HI][HCl]


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