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Chapter 10 Properties of Solids and Liquids
10.5 Changes of State Learning Goal Describe the changes of state between solids, liquids, and gases; calculate the energy involved.
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Change of State Matter undergoes a change of state when it is converted from one state to another at a constant temperature. Figure Changes of state include melting and freezing, boiling and condensation, sublimation and deposition.
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Melting and Freezing A substance changes from a solid to a liquid at its melting point (mp) changes from a liquid to a solid at its freezing point (fp) Water has a freezing (melting) point of 0 °C.
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Heat of Fusion The heat of fusion is the energy that must be added to convert exactly 1 g of solid to a liquid at its melting point. For H2O, 334 J of heat is needed to melt 1 g of ice at its melting point (0 °C). H2O(s) J/g H2O(l) Endothermic
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Heat of Fusion, H2O The heat of fusion is also the quantity of heat that must be removed to freeze 1 g of water at its freezing point (0 °C). For H2O, 334 J of heat is removed to freeze 1 g of ice at its melting point (0 °C). H2O(l) H2O(s) J/g Exothermic
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Heat of Fusion, H2O The heat of fusion for water can be used as a conversion factor. 1 g H2O = 334 J Calculating heat to melt (or freeze) water, we use the following equation:
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Guide to Calculations, Heat of Fusion
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Learning Check How much heat in joules is needed to melt 15.0 g of ice (H2O)?
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Solution How much heat in joules is needed to melt 15.0 g of ice (H2O)? Step 1 State the given and needed quantities. Given: 15.0 g of H2O(s) at 0 °C Need: joules to melt ice at 0 °C
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Solution How much heat in joules is needed to melt 15.0 g of ice (H2O)? Step 2 Write a plan to convert the given quantity to the needed quantity.
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Solution How much heat in joules is needed to melt 15.0 g of ice (H2O)? Step 3 Write the heat of fusion factor and any metric factor needed.
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Solution How much heat in joules is needed to melt 15.0 g of ice (H2O)? Step 4 Set up the problem and calculate the needed quantity.
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Evaporation, Boiling, and Condensation
Evaporation occurs when water molecules gain sufficient energy to escape the liquid surface and enter the gas phase.
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Evaporation, Boiling, and Condensation
At the boiling point, the molecules have enough energy to overcome their attractive forces and become a gas.
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Evaporation, Boiling, and Condensation
In condensation water vapor is converted to a liquid as the water molecules lose kinetic energy and slow down. Condensation occurs at the same temperature as boiling, but heat is removed.
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Heat of Fusion, Vaporization for Selected Substances
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Heat of Vaporization versus Heat of Fusion
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Heat of Vaporization, H2O
The heat of vaporization for water can be used as a conversion factor. 1 g H2O = 2260 J To calculate the heat needed to boil (or vaporize) water, we use the following equation:
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Guide to Calculations, Heat of Vaporization
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Learning Check How many kilojoules (kJ) are released when g of steam from a volcano condenses at 100 °C ?
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Solution How many kilojoules (kJ) are released when 50.0 g of steam from a volcano condenses at 100 °C ? Step 1 State the given and needed quantities. Given: 50.0 g of H2O(g) Need: kilojoules released to condense H2O(g) to H2O(l)
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Solution How many kilojoules (kJ) are released when 50.0 g of steam from a volcano condenses at 100 °C ? Step 2 Write a plan to convert the given quantity to the needed quantity.
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Solution How many kilojoules (kJ) are released when 50.0 g of steam from a volcano condenses at 100 °C ? Step 3 Write the heat of vaporization factor and any metric factor needed.
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Solution How many kilojoules (kJ) are released when 50.0 g of steam from a volcano condenses at 100 °C ? Step 4 Set up the problem and calculate the needed quantity.
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Heating and Cooling Curves
All the changes of state during the heating of a solid can be illustrated using a heating curve. Heating curves are a graph, with temperature on the vertical axis and addition of heat on the horizontal axis. Heating curves illustrate a change of state, using a horizontal line in temperature of a substance as energy is added or released by a sloped line
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Heating Curve, H2O Figure A heating curve diagrams the temperature increases and changes of state as heat is added.
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Cooling Curve, H2O The cooling curve is a diagram of the cooling process and the reverse of a heating curve. A cooling curve for water illustrates the change in temperature and changes of state as heat is removed.
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Combining Energy Calculations
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Learning Check A plateau (horizontal line) on a heating curve represents A. a temperature change B. a constant temperature C. a change of state A sloped line on a heating curve represents
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Solution A plateau (horizontal line) on a heating curve represents C. a change of state A sloped line on a heating curve represents A. a temperature change
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Learning Check Use the cooling curve for H2O to answer each. A. Water condenses at a temperature of (1) 0 °C (2) 50 °C (3) 100 °C B. At a temperature of 0 °C, liquid water (1) freezes (2) melts (3) changes to a gas C. When water freezes, heat is (1) removed (2) added
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Solution Use the cooling curve for H2O to answer each. A. Water condenses at a temperature of (3) 100 °C B. At a temperature of 0 °C, liquid water (1) freezes C. When water freezes, heat is (1) removed
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Learning Check To reduce a fever, an infant is packed in 250. g of ice H2O(s). If the ice (at 0 °C) melts and warms to body temperature (37.0 °C), how many joules are removed?
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Solution If 250. g ice (at 0 °C) melts and warms to 37.0 °C, how many joules are removed? Step 1 State the given and needed quantities. Given: 250. g H2O(s) H2O(l) water at 37.0 °C Need: joules to melt H2O(s) at 0 °C and warm to 37.0 °C
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Solution If 250. g ice (at 0 °C) melts and warms to 37.0 °C, how many joules are removed? Step 2 Write a plan to convert the given to the needed quantity.
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Solution If 250. g ice (at 0 °C) melts and warms to 37.0 °C, how many joules are removed? Step 2 Write a plan to convert the given to the needed quantity.
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Solution If 250. g ice (at 0 °C) melts and warms to 37.0 °C, how many joules are removed? Step 3 Write the conversion factors needed.
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Solution If 250. g ice (at 0 °C) melts and warms to 37.0 °C, how many joules are removed? Step 4 Set up the problem and calculate the needed quantity.
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Solution If 250. g ice (at 0 °C) melts and warms to 37.0 °C, how many joules are removed? Step 4 Set up the problem and calculate the needed quantity.
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Concept Check
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