Download presentation
Presentation is loading. Please wait.
1
Lecture 6: Inbreeding and Heterosis
2
Inbreeding Inbreeding = mating of related individuals
Often results in a change in the mean of a trait Inbreeding is intentionally practiced to: create genetic uniformity of laboratory stocks produce stocks for crossing (animal and plant breeding) Inbreeding is unintentionally generated: by keeping small populations (such as is found at zoos) during selection
3
Genotype frequencies under inbreeding
The inbreeding coefficient, F F = Prob(the two alleles within an individual are IBD) -- identical by descent Hence, with probability F both alleles in an individual are identical, and hence a homozygote With probability 1-F, the alleles are combined at random
4
Alleles IBD Random mating Genotype Alleles IBD Alleles not IBD
frequency A1A1 Fp (1-F)p2 p2 + Fpq A2A1 (1-F)2pq A2A2 Fq (1-F)q2 q2 + Fpq
5
Changes in the mean under inbreeding
Genotypes A1A1 A1A2 A2A2 0 a+d 2a freq(A1) = p, freq(A2) = q Using the genotypic frequencies under inbreeding, the population mean mF under a level of inbreeding F is related to the mean m0 under random mating by mF = m0 - 2Fpqd
6
For k loci, the change in mean is
Here B is the reduction in mean under complete inbreeding (F=1) , where • There will be a change of mean value dominance is present (d not zero) • For a single locus, if d > 0, inbreeding will decrease the mean value of the trait. If d < 0, inbreeding will increase the mean • For multiple loci, a decrease (inbreeding depression) requires directional dominance dominance effects di tending to be positive. • The magnitude of the change of mean on inbreeding depends on gene frequency, and is greatest when p = q = 0.5
7
Inbreeding Depression and Fitness traits
Inbred Outbred
8
Define ID = 1-mF/m0 = 1-(m0-B)/m0 = B/m0
Drosophila Trait Lab-measured ID = B/m0 Viability 0.442 (0.66, 0.57, 0.48, 0.44, 0.06) Female fertility 0.417 (0.81, 0.35, 0.18) Female reproductive rate 0.603 (0.96, 0.57, 0.56, 0.32) Male mating ability 0.773 (0.92, 0.76, 0.52) Competitive ability 0.905 (0.97, 0.84) Male fertility 0.11 (0.22, 0) Male longevity 0.18 Male weight 0.085 (0.1, 0.07) Female weight -0.10 Abdominal bristles 0.077 (0.06, 0.05, 0) Sternopleural bristles -.005 (-0.001, 0) Wing length 0.02 (0.03, 0.01) Thorax length 0.02
9
Why do traits associated with fitness show inbreeding depression?
Two competing hypotheses: Overdominance Hypothesis: Genetic variance for fitness is caused by loci at which heterozygotes are more fit than both homozygotes. Inbreeding decreases the frequency of heterozygotes, increases the frequency of homozygotes, so fitness is reduced. Dominance Hypothesis: Genetic variance for fitness is caused by rare deleterious alleles that are recessive or partly recessive; such alleles persist in populations because of recurrent mutation. Most copies of deleterious alleles in the base population are in heterozygotes. Inbreeding increases the frequency of homozygotes for deleterious alleles, so fitness is reduced.
10
Estimating B In many cases, lines cannot be completely inbred due to either time constraints and/or because in many species lines near complete inbreeding are nonviable In such cases, estimate B from the regression of mF on F, mF = m0 - BF m0 mF F 1 m0 - B If epistasis is present, this regression is non-linear, with CkFk for k-th order epistasis
11
Minimizing the Rate of Inbreeding
Avoid mating of relatives Maximize effective population size Ne Ne maximized with equal representation Ne decreases as the variance of contributed offspring increases Contribution (number of sibs) from each parent as equal as possible Sex ratio as close to 1:1 as possible When sex ratio skewed (r dams/sires ), every male should contribute (exactly) one son and r daughters, while every female should leave one daughter and also with probability 1/r contribute a son
12
Line Crosses: Heterosis
When inbred lines are crossed, the progeny show an increase in mean for characters that previously suffered a reduction from inbreeding. This increase in the mean over the average value of the parents is called hybrid vigor or heterosis A cross is said to show heterosis if H > 0, so that the F1 mean is average than the average of both parents.
13
Expected levels of heterosis
If pi denotes the frequency of Qi in line 1, let pi + di denote the frequency of Qi in line 2. The expected amount of heterosis becomes • Heterosis depends on dominance: d = 0 = no inbreeding depression and no. heterosis as with inbreeding depression, directional dominance is required for heterosis. • H is proportional to the square of the difference in gene frequency Between populations. H is greatest when alleles are fixed in one population and lost in the other (so that | di| = 1). H = 0 if d = 0. • H is specific to each particular cross. H must be determined empirically, since we do not know the relevant loci nor their gene frequencies.
14
Heterosis declines in the F2
In the F1, all offspring are heterozygotes. In the F2, random mating has occurred, reducing the frequency of heterozygotes. As a result, there is a reduction of the amount of heterosis in the F2 relative to the F1, Since random mating occurs in the F2 and subsequent generations, the level of heterosis stays at the F2 level.
15
Crossing Schemes to Reduce the Loss of Heterosis: Synthetics
Take n lines and construct an F1 population by making all pairwise crosses Allow random mating from the F2 on to produce a synthetic population H/n ( ) Only 1/n of heterosis lost vs. 1/2
16
Schemes to Reduce the Loss of Heterosis: Rotational Crossbreeding
Suppose we have three “pure” lines, A, B, C Originally suggested for pig populations Dam Sire A B AxB C Each generation, cross a crossbred dam with a sire from the next line in the sequence AxBxC A
17
b R = S C ° P 2 1 * n For a two-line rotation
H/3 vs. H/2 for synthetics General expression for n-line rotation Subset of all pair-wise crosses (non-adjacent Crossed lines) Average of parental lines b R n = S C P 2 1 * Average of all pair-wise crosses Can show the expected mean is greater than the corresponding n-line synthetic
18
Individual vs. Maternal Heterosis
Individual heterosis enhanced performance in a hybrid individual Maternal heterosis enhanced maternal performance (such as increased litter size and higher survival rates of offspring) Use of crossbred dams Maternal heterosis is often comparable, and can be greater than, individual heterosis
19
Individual vs. Maternal Heterosis in Sheep traits
Individual H Maternal H total Birth weight 3.2% 5.1% 8.3% Weaning weight 5.0% 6.3% 11.3% Birth-weaning survival 9.8% 2.7% 12.5% Lambs reared per ewe 15.2% 14.7% 29.9% Total weight lambs/ewe 17.8% 18.0% 35.8% Prolificacy 2.5% 5.7%
20
Agricultural importance of heterosis
Crosses often show high-parent heterosis, wherein the F1 not only beats the average of the two parents (mid-parent heterosis), it exceeds the best parent. Crop % planted as hybrids % yield advantage Annual added yield: % Annual added yield: tons Annual land savings Maize 65 15 10 55 x 106 13 x 106 ha Sorghum 48 40 19 13 x 106 9 x 106 ha Sunflower 60 50 30 7 x 106 6 x 106 ha Rice 12 4 15 x 106
21
Variance Changes Under Inbreeding
Inbreeding increases the variation between populations (i.e., variation in the means of the populations) Inbreeding reduces variation within each population F = 1 F = 3/4 F = 0 F = 1/4
22
Variance Changes Under Inbreeding
General F = 1 F = 0 Between lines 2FVA 2VA Within Lines (1-F) VA VA Total (1+F) VA
23
Mutation and Inbreeding
• Eventually these two forces balance, leading to an equilibrium level of genetic variance reflecting the balance between loss from drift, gain from mutation • As lines lose genetic variation from drift, mutation introduces new variation VM = new mutation variation each generation, typically VM = 10-3 VE Assuming: Strictly neutral mutations Strictly additive mutations Symmetrical distribution of mutational effects
24
Between-line Divergence
The between-line variance in the mean (VB) in generation t is For large t, the asymptotic rate is 2VMt Implications: Two identical lines will have their difference in means eventually (approximately) following a normal distribution with mean 0 and variance 2VMt, e.g., m(1) - m(2) ~ N(0, 2VMt)
Similar presentations
© 2024 SlidePlayer.com. Inc.
All rights reserved.