Download presentation
Presentation is loading. Please wait.
Published byDale Heath Modified over 6 years ago
1
On average, there are 3(4.42) =13.26 claims waiting be processed.
Problem 8.8 Ri = 3.5 /week Ri = 3.5/5 = .7 /day Tp = 1.2 day Rp = 1/1.2 = .833 /day a1) Across all districts, on average, how many claims are waiting to be processed. On average, there are 3(4.42) = claims waiting be processed.
2
A2) what fraction of claims is completed in less than 10 business days
A2) what fraction of claims is completed in less than 10 business days? T≤ 10 Whenever there is no info on CV, assume Poisson Process In the above example with utilization = 0.84 Suppose we check the claim processor at 100 random times. On average on how many times is s/he processing a claim? 84% one customer, 16% no customer. On average .84 customer are in the server. In a single server ρ customer are served, in multi server cρ customers
3
We can reach the same conclusion using the Little’s law
4
We need to compute T: Average time in the system
A2) what fraction of claims is completed in less than 10 business days? T≤ 10 We need to compute T: Average time in the system Alternatively
5
Three Servers, Poisson Process
Combined Individual
6
b) One Server, Reduced Cp from 1 to .5
Rduction is service time variability, improves the probability from 73.6% to 86%
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.