1. Kp = Kc(RT)∆n Kp = Kc(RT)∆n = 0.042(RT)-1 = 0.042/RT
#17..ch15)
PCl3 + Cl2  PCl5 ∆n = -1
Kp = Kc(RT)∆n = 0.042(RT)-1 = 0.042/RT
Kp = = = 0.001
( )(500)
Kp = Kc(RT)∆n

2. #20 ch15)
A) 2 NO(g) + O2(g)  2 NO2 (g)
Kp forward = P2 NO = * 104
P2 NO * P O2 B)
2 NO2 (g)  2 NO(g) + O2(g)
Kp reverse = P2 NO * P O2 = = * 10-5
P2 NO * 104
NO2 is favored as the K of its formation is greater than for its consumption.

3. #27 ch 15)
Kc = [H2 ] [ I2 ] = (4.79 * 10-4)( 4.79 * 10-4) = =
[HI] (3.53 * 10-3)2
#30 CH 15)
Kp = P PCl = ATM = 66.8
P PCl3 * P CL ATM * ATM
PRODUCTS ARE FAVORED, K > 1
2 HI (g)  H2(g) + I2(g)
PCl3 (g) + Cl2 (g)  PCl5 (g)