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Gas properties and temperature

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Presentation on theme: "Gas properties and temperature"— Presentation transcript:

1 Gas properties and temperature
December 19, 2017 Gas properties and temperature Matter and energy Learning Target: I CAN Develop a relationship between volume and pressure and apply Boyle’s Law to gas law problems

2 Do Now (4 min) Describe two properties for ideal gases.
December 19, 2017 Learning target: I can Develop a relationship between volume and pressure and apply Boyle’s Law to gas law problems Do Now: (Answer on your Do Now Sheet) Describe two properties for ideal gases. What does it mean to be ideal? Learning Target: I CAN Develop a relationship between volume and pressure and apply Boyle’s Law to gas law problems

3 December 19, 2017 Units of Temperature!!!! oF oC K = Kelvin!! *Your new best friend 0oC = frozen water K = oC + 273 Learning Target: I CAN Develop a relationship between volume and pressure and apply Boyle’s Law to gas law problems

4 Units of Temperature!!!! 0 Kelvin = no motion, no speed of molecules
Learning Target: I CAN Develop a relationship between volume and pressure and apply Boyle’s Law to gas law problems December 19, 2017

5 December 19, 2017 Boyle’s law You have your handy balloon all blown up. What happens to the volume if you then put force against the balloon? AKA: increase the pressure? What if you could stretch out the balloon, what would happen to the pressure? Learning Target: I CAN Develop a relationship between volume and pressure and apply Boyle’s Law to gas law problems

6 December 19, 2017 Standard temperature: 273 K = 00C Standard pressure: 1 atm Boyle’s law Example #1: 2.00 L of a gas is at mmHg pressure. What is its volume at standard pressure? P1 V1 = P2 V2 740.0 mmHg 2.00 L 760 mmHg FIND ME!! Learning Target: I CAN Develop a relationship between volume and pressure and apply Boyle’s Law to gas law problems

7 December 19, 2017 Standard temperature: 273 K = 00C Standard pressure: 1 atm Boyle’s law Use P1V1 = P2V2 to find V2 (740 mmHg)(2.00 L) = (760 mmHg)(V2) V2 = [(740 mmHg)(2.00 L)] / (760 mmHg) V2 = 1.95 L Learning Target: I CAN Develop a relationship between volume and pressure and apply Boyle’s Law to gas law problems

8 December 19, 2017 Standard temperature: 273 K = 00C Standard pressure: 1 atm Boyle’s law Example #2: 5.00 L of a gas is at 1.08 atm. What pressure is obtained when the volume is 10.0 L? P1 V1 = P2 V2 1.08 atm 5.00 L FIND ME!! 10.0 L Learning Target: I CAN Develop a relationship between volume and pressure and apply Boyle’s Law to gas law problems

9 December 19, 2017 Standard temperature: 273 K = 00C Standard pressure: 1 atm Boyle’s law Use P1V1 = P2V2 to find P2 (1.08 atm)(5.00 L) = (P2)(10.0 L) P2 = [(1.08 atm)(5.00 L)] / (10.0 L) P2 = _________________ Learning Target: I CAN Develop a relationship between volume and pressure and apply Boyle’s Law to gas law problems

10 December 19, 2017 Standard temperature: 273 K = 00C Standard pressure: 1 atm You try: Boyle’s law Example #3: 2.50 L of a gas was at an unknown pressure. However, at standard pressure, its volume was measured to be 8.00 L. What was the unknown pressure? P1 V1 = P2 V2 FIND ME!! Learning Target: I CAN Develop a relationship between volume and pressure and apply Boyle’s Law to gas law problems

11 December 19, 2017 pair work (15 min) Work in PAIRS Draw relationship boxes AND write out equations! Learning Target: I CAN Develop a relationship between volume and pressure and apply Boyle’s Law to gas law problems

12 December 19, 2017 Exit ticket (3 min) EXIT TICKET: complete on a separate sheet of paper: What happens to the pressure when the volume is doubled? Learning Target: I CAN Develop a relationship between volume and pressure and apply Boyle’s Law to gas law problems


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