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Factoring Trinomials of the Type x2 + bx + c

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Presentation on theme: "Factoring Trinomials of the Type x2 + bx + c"— Presentation transcript:

1 Factoring Trinomials of the Type x2 + bx + c
ALGEBRA 1 LESSON 9-5 (For help, go to Skills Handbook page 721.) List all of the factors of each number. 5-7

2 Factoring Trinomials of the Type x2 + bx + c
ALGEBRA 1 LESSON 9-5 Solutions 1. Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24 2. Factors of 12: 1, 2, 3, 4, 6, 12 3. Factors of 54: 1, 2, 3, 6, 9, 18, 27, 54 4. Factors of 15: 1, 3, 5, 15 5. Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36 6. Factors of 56: 1, 2, 4, 7, 8, 14, 28, 56 7. Factors of 64: 1, 2, 4, 8, 16, 32, 64 8. Factors of 96: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 96 5-7

3 Factoring Trinomials of the Type x2 + bx + c
ALGEBRA 1 LESSON 9-5 Factor x2 + 8x + 15. Find the factors of 15. Identify the pair that has a sum of 8. Factors of 15 Sum of Factors 1 and 3 and x2 + 8x + 15 = (x + 3)(x + 5). = x2 + 5x + 3x + 15 Check: x2 + 8x (x + 3)(x + 5) = x2 + 8x + 15 5-7

4 Factoring Trinomials of the Type x2 + bx + c
ALGEBRA 1 LESSON 9-5 Factor c2 – 9c + 20. Since the middle term is negative, find the negative factors of 20. Identify the pair that has a sum of –9. (-)Factors of Sum of Factors –1 and –20 –21 –2 and –10 –12 –4 and –5 –9 c2 – 9c + 20 = (c – 5)(c – 4) 5-7

5 Factoring Trinomials of the Type x2 + bx + c
ALGEBRA 1 LESSON 9-5 Factor each expression. 1. c2 + 6c x2 – 11x + 18 3. m2 – 2mn + n2 (c + 3)(c + 3) (x – 2)(x – 9) (m – n)(m – n) 5-7


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