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Solving Inequalities Using Addition and Subtraction
ALGEBRA 1 LESSON 3-2 pages 142–145 Exercises 1. 5 2. 8 3. 4.3 4. x > 11 5. t < 1 6. b < –4 7. d 10 8. s –4 9. r 9 10. n > 10 11. w –2 12. d > 3 13. y –4 14. q < 3 15. x 16. r < 4.5 17. m < –1.6 18. b < 19. n > 3 20. 2 21. 23. w 5; 1 2 < – 1 3 > – 1 2 > – > – < – 5 3 < – < – 3-2
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Solving Inequalities Using Addition and Subtraction
ALGEBRA 1 LESSON 3-2 24. m > –8; 25. b > –7; 26. a –6; 27. r –6; 28. k 1; 29. x < –1; 30. p > –6; 31. z –1; 32. y < 5.5; 33. m > –1 ; 34. a –0.3; 35. p > –7; 36. h – ; 37. d > –1.5; 38. t < – ; 39. s , $1363 40. s , $3.50 41. r , 21 reflectors 42. Add 4 to each side. 43. Subtract 9 from each side. 44. Add to each side. 45. w 11 46. c 3 47. y < 3.1 1 2 48. n < –5 49. z < –9.7 50. y < –3.2 51. t > 52. v 16 53. k –8.1 54. b < 6 55. m –3.5 56. k 4 57. h – 58. x –5.7 59. w < –14 4 5 < – 1 2 < – 1 6 > – < – < – < – > – > – > – > – < – 1 2 3 4 < – 1 2 1 2 > – > – < – < – < – 3-2
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Solving Inequalities Using Addition and Subtraction
ALGEBRA 1 LESSON 3-2 60. w –1 61. x < 16 62. m > 5.5 63. t 64. k < 2 65. n < 6 66. m 5 67. s > 10.3 68. a. yes b. no c. Answers may vary. Sample: The = sign indicates that each side is equal, so the two sides may be interchanged. 1 6 < – The < sign does not indicate equality. One side cannot be both greater than and less than the other side. 69. a. Let n = points scored on floor exercises. n ; n b. Your sister must score 9.1 points or more to qualify for regional gymnastics competition. c. Answers may vary. Sample: 9.1, 9.2, 9.3 70. nearly 51.2 MB 71. at least $15.50 or more points 73. a-b. Check students’ work. > – > – > – 3 5 < – 3-2
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Solving Inequalities Using Addition and Subtraction
ALGEBRA 1 LESSON 3-2 79. r < –2 80. r –13 81. a –25 m 83. d > –8 84. y < 6 85. a 24 86. a < –8 87. a. a > c – b b. b > a – c c. c > b – a d. The length of the third side must be greater than the difference of the lengths of the other two sides. 74. a. No; the solution is z , so z 14 is not correct. b. Answers may vary. Sample: Substituting values does not work because there is always the possibility that the solution lies between values that make the inequality true and a value that does not. 75. x 1 76. n < 5 77. t –3 78. k > 10 88. not true; sample counter example: for a = 5 and b = –6, 5 –(–6) < 5 +(–6) 89. true 90. true 91. not true; sample counter example: for a = 0, b = 1, and c = –2, 0 < 1 and 0 < 1 + (–2) 92. Answers may vary. Sample: For x = 2, y = 1, z = 4, and w = 3, 2 > 1 and 4 > 3, but 2 – 4 > 1 – 3. / > – > – > – > – < – < – > – < – 3-2
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Solving Inequalities Using Addition and Subtraction
ALGEBRA 1 LESSON 3-2 93. B 94. G 95. A 96. I 97. D 98. [2] at least 33 points; 24(19.5) + x > 25(20) 468 + x > 500 x > 32 (OR equivalent explanation) [1] incorrect answer OR no work or explanation 99. Let c = length of octopus in feet. c 10 100. Let h = distance in miles a hummingbird migrates. h > 1850 101. Let a = average. a 90 102. Let p = number of pages to read. p 25 104. –1 105. –12 106. 4 108. –18 109. –28 113. 7 > – > – < – 3-2
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