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Warm-Up! π(π₯) is a continuous function defined on the interval [β2,2]. π β2 =β3, and π 2 =7. Which of the following must be true. There exists a value π₯=π, where π π =0 πβ²(π₯)>0 for all values of π₯ There exists a value π₯=π, where π π =β5 I. III. I. II. II. III. I. Not enough information to determine.
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Derivative FRQ Practice
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Given the table answer the questions
Use the data in the table to approximate π β² β4.5 and πβ²(β2). Is there a value π₯, β3β€π₯β€β4 at which π β² π₯ =β5? Justify! The function π π₯ =β.64 π₯ 3 β4.9 π₯ 2 β15.37π₯β6 models the table of values. Find the rate of change when π₯=β1 π -2 -3 -4 -5 -6 -7 π(π₯) 10.2 13.5 18.5 27.9 49.3 81.7
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The functions π is defined by π π₯ = 5β π₯ 2 2
Find π β² π₯ Write an equation for the line tangent to the graph of π at π₯=β1 let π be the function defined by π π₯ = π(π₯), 1β€π₯<3 &π₯+10, 3β€π₯β€7 , Is π continuous at 3? Why?
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π π π<π<π π π<π<π π π<π<π π π(π₯) 7 Positive 2 4 πβ²(π₯) β3 Negative π(π₯) 9 β4 πβ²(π₯) β7 β2 The twice differentiable functions π and π are defined for all real numbers π₯. Values of π, π β² , π, and πβ² for various values of π₯ are given in the table above. Find the π₯βcoordinate of each relative minimum of π on the interval [4,7]. Justify your answers. Explain why there must be a value π, for 5<π<6, such that π β²β² π =0 Function β is defined by β π₯ = π π₯ Find ββ²(2). Show the computations that lead to your answer.
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Differentiate the function π π₯ = sin 3π₯ + cos π₯ β3 sin 2 π₯ 2
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