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Published bySri Budiman Modified over 5 years ago
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Bohr predicted that the energy of an electron in a hydrogen atom is
E = - k ____ n2 E is the energy of the e- k is the Bohr Constant, x J n is the Bohr Orbit For energy values: Positive means repulsive energy (because it’s a high value) Negative means attractive energy (because it’s a low value) Therefore, an e-s energy in an atom will always be negative EX3-1 (of 11)
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Calculate the energy of an e- in the 3rd Bohr Orbit of a hydrogen atom
E = - k ____ n2 = x J __________________ 32 = x J EX3-2 (of 11)
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Calculate the energy change when an e- drops from n = 2 to n = 1 in a hydrogen atom.
E2 = - k ____ n2 = x J ___________________ 22 = x J E1 = - k ____ n2 = x J ___________________ 12 = x J EX3-3 (of 11)
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Calculate the energy change when an e- drops from n = 2 to n = 1 in a hydrogen atom.
The energy change (ΔE) is equal to the final energy state minus the initial energy state: ΔE = E1 - E2 = ( x J) – ( x J) = x J For CHANGES in energy: Positive means energy was absorbed Negative means energy was released Therefore, this hydrogen atom released energy EX3-4 (of 11)
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Calculate the energy change when an e- drops from n = 2 to n = 1 in a hydrogen atom.
The energy released is given off as a photon, and the photon’s energy is the absolute value of ΔE: Ephoton = | ΔE │ = | x J │ = x J EX3-5 (of 11)
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If an electron is removed from an atom, the atom has been IONIZED
Calculate the ionization energy of a ground state hydrogen atom E1 = - k ____ n2 = x J ___________________ 12 = x J Eout = 0 J EX3-6 (of 11)
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If an electron is removed from an atom, the atom has been IONIZED
Calculate the ionization energy of a ground state hydrogen atom ΔE = Eout - E1 = (0 J) – ( x J) = x J The positive energy change means that the hydrogen atom absorbed this energy to release the electron EX3-7 (of 11)
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Measuring the Wavelengths in Hydrogen’s Emission Spectrum
EX3-8 (of 11)
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e = λ sin ϴ = e/d d sin ϴ = e = λ EX3-9 (of 11)
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tan ϴ = x/l ϴ = tan-1 (x/l) remember: λ = d sin ϴ λ = d sin [tan-1 (x/l)] EX3-10 (of 11)
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