Download presentation
Presentation is loading. Please wait.
1
Hour 33 Coupled Oscillators I
Physics 321 Hour 33 Coupled Oscillators I
2
Example I x1 x2 k1 k2 k3 π= 1 2 π 1 π₯ π 2 π₯ 2 2 π= 1 2 π 1 π₯ π 2 π₯ 2 β π₯ π 3 π₯ 2 2 πΏ= 1 2 π 1 π₯ π 2 π₯ 2 2 β 1 2 π 1 π₯ 1 2 β 1 2 π 2 π₯ 2 β π₯ β 1 2 π 3 π₯ 2 2
3
Example I x1 x2 k1 k2 k3 πΏ= 1 2 π 1 π₯ π 2 π₯ 2 2 β 1 2 π 1 π₯ 1 2 β 1 2 π 2 π₯ 2 β π₯ β 1 2 π 3 π₯ 2 2 π 1 π₯ 1 =β π 1 π₯ 1 + π 2 π₯ 2 β π₯ 1 =β π 1 + π 2 π₯ 1 + π 2 π₯ 2 π 2 π₯ 2 =β π 3 π₯ 2 β π 2 π₯ 2 β π₯ 1 =β π 2 + π 3 π₯ 2 + π 2 π₯ 1
4
Example I x1 x2 k1 k2 k3 π π π₯ π₯ 2 =β π 1 + π 2 β π 2 βπ 2 π 2 + π π₯ 1 π₯ 2 π π₯ =βπ π₯
5
Normal Modes Assume solutions of the form: π₯ 1 π‘ = π΄ 1 sin ππ‘+ π 1
Note that π is the same in both equations! β This defines a βnormal mode.β Then π π₯ =β π 2 π π₯ =βπ π₯
6
Normal Modes - Method 1 π π₯ =β π 2 π π₯ =βπ π₯ β det πβ π 2 π =0
π π₯ =β π 2 π π₯ =βπ π₯ β det πβ π 2 π =0 π 1 + π 2 β π 2 π 1 β π 2 βπ 2 π 2 + π 3 β π 2 π 2 =0 Modified eigenvalue problem Solve for π 2 Use πβ π 2 π π₯ 1 π₯ 2 =0 to solve for π₯ 1 and π₯ 2 Easiest by hand.
7
Normal Modes - Method 2 π π₯ =β π 2 π π₯ =βπ π₯ π β1 π π₯ = π 2 π₯
π π₯ =β π 2 π π₯ =βπ π₯ π β1 π π₯ = π 2 π₯ β det π β1 πβ π 2 π =0 Standard eigenvalue problem Eigenvalues are π 2 Eigenvectors are normal modes Easiest with Mathematica
8
Examples coupled oscillators.nb normal coords.nb
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.