1. What genetic principles account for the passing of traits from parents to offspring?

2. Mendel and the Gene Idea
Chapter 14
Mendel and the Gene Idea

3. Background
The earliest hypothesis to inheritance was the “blending hypothesis” that stated that we are a blend of our parents.
Imagine mixing black and white paint in order to get grey. Would it EVER be possible to keep mixing the “offspring” to get white paint again?
No- This hypothesis was shown to be incorrect.

4. Background
The next hypothesis and is called the “Particulate (or gene) idea”.
- Parents pass on heritable units (“particles”- or genes)
- Was introduced by Gregor Mendel (Father of Genetics) after his work with pea plants.
- Looked at characters (such as color) and traits (such as white or red)

5. Gregor Mendel
Animation

7. Important Terms
True breeding- When true breeding plants self pollinate, offspring are ALWAYS the same as the parents.
IE- Plant AA self pollinates and produces another AA “PURE BREEDS”
- Mix a true breeding red with a true breeding white to produce a hybrid (mix)

9. Important Terms Generations: - P- Parent generation
- F1- First generation offspring
- F2- Second generation offspring
- F3….etc
Progeny = offspring

11. Mendel’s Rules Rules Mendel established
Ted Ed Animation
Rules Mendel established
1) Alternative versions of genes account for variations in inherited characters (purple or white flowers on peas). The alternative versions of these genes are called alleles.
*Think of TRAITS as CATEGORIES and ALLELES as OPTIONS within each category!
Ex. Hair color= trait; Alleles = Red allele, blonde allele, black allele, brown allele, etc.

12. Mendel’s Rules
2) For each characteristic, an organism inherits two alleles- one from each parent

13. Mendel’s Rules
3) If the two genes differ at the locus (location of certain gene on the chromosome) then the one that determines organism’s trait is dominant and the trait that cannot be seen is recessive

14. Mendel’s Rules
4) LAW OF SEGREGATION: The two alleles for a heritable trait separate during meiosis and end up in different gametes

15. Punnett Squares
We can illustrate likelihood of inheritance by completing a Punnett square (probability square)
- Dominant trait will be shown as uppercase letters
- Recessive trait will be shown as lowercase letters
*Same letter for one trait! R= yellow peas, r=green peas
USED “R” for both because still one trait of PEA COLOR! Letter doesn’t matter

16. Other vocab. you need to know
Homozygous- Identical alleles (AA or aa)
prefix homo = “same”; MUST CLARIFY homozygous dominant or homozygous recessive
Heterozygous- Differing alleles (Aa)
prefix hetero = “different”
Phenotype- “Visible” trait (cannot ALWAYS be actually seen with the eyes) *physical look
Genotype- Genetic makeup
*allele letter combinations

17. Clarify which one!
Clarify which one!

18. Punnett Squares
Test cross- A test completed to see if a parent is homozygous dominant or heterozygous. Cross parent in question with a homozygous recessive to determine parent’s genotype.

20. Punnett Squares and the Law of Independent Assortment
- In a monohybrid cross, only one trait will be looked at. IE- cross AA with aa
- In a dihybrid cross, two traits will be looked at. IE- cross AABB with AaBb
*2 different letters, 2 different traits
(A’s for pea color, B’s for pea shape)

21. LAW OF INDEPENDENT ASSORTMENT
Two alleles segregate INDEPENDENTLY of each other (law does not always apply to genes very close to each other on a single chromosome)
*for dihybrid or more- traits don’t travel together! Just because it’s yellow, doesn’t mean it will also always be wrinkled!

23. Punnett Squares
A common ratio you should know for a dihybrid cross is when we cross two completely heterozygous (AaBb x AaBb) individuals with each other= 9:3:3:1
* 9= dominant #1, dominant #2
3= dominant #1, recessive #2
3= recessive #1, dominant #2
1= recessive #1, recessive #2

24. Let’s Practice!

25. Q.Q. 1/11/19 Independent Assortment Imagine crossing a pea heterozygous at the loci for flower color (white & purple) and seed color (yellow & green) with a second pea homozygous for flower color (white) and seed color (yellow). What types of gametes will the first pea produce?
two gamete types: white/white and purple/purple
two gamete types: white/yellow and purple/green
four gamete types: white/yellow, white/green, purple/yellow, purple/green
four gamete types: white/purple, yellow/green,white/white, and purple/purple
Answer: c
The purpose of this question is to help students figure out gamete types—a step they often rush past. Students need to realize that gametes are haploid and that each gamete contains one, and only one, allele for each of the traits being studied. The presence of the second pea in the question stem is a distracter. Answer a is wrong because it shows gametes with two alleles for flower color and no alleles for seed color. Answer b is wrong because it shows only two possible gamete types. Answer c is right because it shows all four possible gamete types. Answer d is wrong because it shows gametes that are diploid for one trait and containing an allele for only one locus. Answer e is wrong because it shows a gamete diploid for both loci.

26. Q.Q. 1/10/19 Independent Assortment Imagine crossing a pea heterozygous at the loci for flower color (white & purple) and seed color (yellow & green) with a second pea homozygous for flower color (white) and seed color (yellow). What types of gametes will the first pea produce?
two gamete types: white/white and purple/purple
two gamete types: white/yellow and purple/green
four gamete types: white/yellow, white/green, purple/yellow, purple/green
four gamete types: white/purple, yellow/green, white/white, and purple/purple
Answer: c
The purpose of this question is to help students figure out gamete types—a step they often rush past. Students need to realize that gametes are haploid and that each gamete contains one, and only one, allele for each of the traits being studied. The presence of the second pea in the question stem is a distracter. Answer a is wrong because it shows gametes with two alleles for flower color and no alleles for seed color. Answer b is wrong because it shows only two possible gamete types. Answer c is right because it shows all four possible gamete types. Answer d is wrong because it shows gametes that are diploid for one trait and containing an allele for only one locus. Answer e is wrong because it shows a gamete diploid for both loci.

27. Genetics Notes – PART 2

28. Genetics Videos to watch!
Bozeman Science– Law of Multiplication and addition
Mendelian Genetics- overview

29. Laws of Probability
If a parent is Aa, then there is a ½ chance that a gamete will carry “A” and a ½ chance that a gamete will carry “a”

30. Probability
Multiplication rule- To find out what the outcome is when I flip two coins at the same time (let’s say both land heads up) then we must multiply ½ x ½ = ¼ chance of both being heads up.

31. Practice Problem! - Cross YyRr with YyRr by using probability ONLY
-Think of this as doing 2 monohybrid crosses

32. Cross YyRr with YyRr - ¼ will be YY - ½ Yy - ¼ yy - Cross Rr with Rr
- Cross Yy with Yy
- ¼ will be YY
- ½ Yy
- ¼ yy
- Cross Rr with Rr
- ¼ RR
- ½ Rr
- ¼ rr Y y YY Yy yy R r RR Rr rr

33. Cross YyRr with YyRr
- Probability of YYRR = ¼ (YY) x ¼ (RR)= 1/16 chance - Probability of YyRR = ½ (Yy) x ¼ (RR)= 1/8 chance Y y YY Yy yy R r RR Rr rr

34. Another Problem! Looking at THREE characters
Cross PpYyRr x Ppyyrr. How many offspring would exhibit the recessive phenotypes of at least two of the three characters? P p PP Pp pp Y y Yy yy R r Rr rr

35. Cross PpYyRr x Ppyyrr
List all possible phenotypes that can fulfill this (recessive phenotypes of at least two of the three characters).
ppyyRr
ppYyrr
Ppyyrr
PPyyrr
ppyyrr P p PP Pp pp Y y Yy yy R r Rr rr

36. Cross PpYyRr x Ppyyrr
ppyyRr ¼ x ½ x ½ = 1/16 ppYyrr ¼ x ½ x ½ = 1/16 Ppyyrr ½ x ½ x ½ = 2/16 PPyyrr ¼ x ½ x ½ = 1/16 ppyyrr ¼ x ½ x ½ = 1/16 P p PP Pp pp Y y Yy yy R r Rr rr

37. Cross PpYyRr x Ppyyrr ppyyRr ¼ x ½ x ½ = 1/16 ppYyrr ¼ x ½ x ½ = 1/16
= 6/16 (sum) or 3/ chance of at least two recessive traits

38. Let’s Practice! Ch. 14 Review Packet of Questions
(turn to BACK; last page)
#5 complete the chart #7 #8

39. Exceptions to Mendel’s Rules!
Non-Mendelian genetics or
complex patterns of inheritance
*AKA what Mendel didn’t figure out!

40. 14.3- Dominance- Alleles can show different degrees of dominance
Complete dominance- Mix a white flower pea plant with a red flower pea plant and get a red flower pea plant (completely dominates/takes over expression) *Mendelian
Codominance- Two dominant alleles are BOTH expressed. IE- Blood type IAIB
(“co” - together)

42. AB Blood Types is Codominant = BOTH show up equally
Co-Dominance
Example: The ABO blood type in humans
The alleles for A and B blood types are codominant and both are expressed in the phenotype
AB Blood Types is Codominant = BOTH show up equally

43. “Roan” fur coloring on cows/horses –
Codominance Patterns
“Roan” fur coloring on cows/horses –
2 separate colors show up equally (red/white)

44. Incomplete dominance- One dominant allele is not completely dominant over the other. IE- Snapdragon flowers

46. Frequency of the dominant allele
The dominant allele is not always the most prevalent allele.
IE- Polydactyly. The dominant trait as humans is to have 6 fingers on one hand. The recessive is to only have 5.

47. Multiple alleles can decide a single phenotype. IE- Blood types.

48. Pleiotropy- One gene can have MULTIPLE phenotypic results.
IE- Cystic fibrosis has more than one effect on the body.

49. Epistasis- One gene can affect another gene.
IE- Mouse color. Two traits being looked at.
1) Color: Black = Dominant (BB or Bb) or Brown = recessive (bb)
2) Pigment deposited: Normal= Dominant (CC or Cc) or None (albino) = rec. (cc)
The “pigment deposited” gene decides if any pigment at all will be seen. If the offspring has the recessive “pigment deposited” gene then the mouse will be albino.

51. Polygenetic Inheritance- Additive effect of two or more genes on a single phenotypic character. IE: Gradations of skin color (3 genes)

52. Nature vs. Nurture
Nature vs. Nurture- What really decides a phenotype? Is it the genotype or what is done to the body (such as overeating)?
“Norm of Reaction” for a genotype- A genotype has a range of possible phenotypic outcomes.
Not all traits have this, such as blood type (no phenotypic range)

54. soil pH affects the color of hydrangea flowers –
Nature vs. Nurture
Multifactoral characteristics- Both the genotype and the environment can change a phenotype
Example:
soil pH affects the color of hydrangea flowers –

55. 14.4 Human Traits Human pedigree- Shows generations and traits in a family

56. Mating Pedigree Key Offspring Male Dd Joshua Lambert Abigail Linnell
John
Eddy
Hepzibah
Daggett dd
Jonathan
Elizabeth
Dd Dd dd Dd Dd Dd dd
Female Male
Deaf
Hearing
Pedigree Key
Female
Male
Mating
Offspring
Figure 9.8 B

57. Human Traits
Recessively Inherited Disorders- Can be mild (albinism) to severe (cystic fibrosis)
- A person with a heterozygous genotype is a carrier of the disorder, but often does not express it phenotypically.
Human deafness

58. Recessive Disorders- Most human genetic disorders are recessive
Parents
Offspring
Sperm
Normal Dd 
D d
Eggs D d DD
(carrier) dd
Deaf
Figure 9.9 A

59. Human Traits
- Individuals with these disorders often times do not produce offspring (with exceptions)
- These disorders are NOT spread equally among populations
- Cystic fibrosis- Most common in European descent individuals.
- Sickle cell anemia- Most common in African descent individuals.

60. Human Traits
Dominantly Inherited Disorders- Individuals with dominant phenotype have disorder.
- Achondroplasia- Dwarfism. Effects apparent at birth.
- Huntington’s Disease- No effects until age If a parent has this disorder, there is a 50% chance that their offspring will also have it. (Aa x aa)

61. Dominant Disorders- Some human genetic disorders are dominant
Parents
Offspring
Sperm
Dwarf Dd
Normal dd 
D d
Eggs d
Achondroplasia – cause of dwarfism
Figure 9.9 B

62. Human Traits
Multifactoral diseases- Genotype and environment effect individual. IE- Heart disease.

63. Genetic Testing
- Amniocentesis- The removal of about 10 ml of amniotic fluid to test for certain genetic disorders. Considered time consuming and somewhat dangerous. *Animation
- CVS (Chorionic villus sampling)- Tissue is removed from the placenta. Rapid results via karyotyping. *Animation

65. Sex- Linked Traits
Sex linkage is the phenotypic expression of an allele related to the chromosomal sex of the individual (male or females)

66. Examples: Hemophilia, Color Blindness, and Duchenne Muscular Dystrophy
Sex Linked
Most sex-linked human disorders are due to recessive alleles and are mostly seen in males
Examples: Hemophilia, Color Blindness, and Duchenne Muscular Dystrophy
Queen
victoria
Albert
Alice
Louis
Alexandra
Czar
Nicholas II
of Russia
Alexis
Figure 9.24 A
Figure 9.24 B

67. Another Sex Linked trait!
Linked to Y chromosome (only males)
Example: Hypertrichosis Pinnae Auris
(aka HAIRY EARS!!!)