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12.5: Volumes of Pyramids and Cones
Objective: Use the formula for volume of pyramids and cones to solve problems
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Vocab Volume of a Pyramid π= 1 3 π΅β B = area of base
h = height of pyramid π= 1 3 π΅β
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Example 1 π= 1 3 π΅β π΅=3β3=9 β=7 π=9β7=63 ππ 3
Find the volume of the square pyramid. Label the units. π= 1 3 π΅β π΅=3β3=9 β=7 π=9β7=63 ππ 3
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Example 2 π= 1 3 π΅β π΅= πββ 2 = 5β9 2 =22.5 β=10 π=22.5β10=225 ππ 3
Find the volume of the triangular pyramid. Label the units. π= 1 3 π΅β π΅= πββ 2 = 5β9 2 =22.5 β=10 π=22.5β10=225 ππ 3
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You Try Find the volume of the pentagonal pyramid. Label the units.
Do on your own first!
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You Try π= 1 3 π΅β π΅= 1 2 ππ= 1 2 β3β22=33 β=12 π=33β12=396 ππ 3
Find the volume of the pentagonal pyramid. Label the units. π= 1 3 π΅β π΅= 1 2 ππ= 1 2 β3β22=33 β=12 π=33β12=396 ππ 3
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Vocab Volume of a Cone π= 1 3 Ο π 2 β r = radius of base
h = height of cone π= 1 3 Ο π 2 β
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Example 3 π= 1 3 Ο π 2 β π=5 β=12 π= 1 3 Ο (5) 2 β12=100Ο ππ 3
Find the volume of the cone. Leave your answers in terms of Ο and label the units. π= 1 3 Ο π 2 β π=5 β=12 π= 1 3 Ο (5) 2 β12=100Ο ππ 3
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Example 4 π= 1 3 Ο π 2 β π=9.1 β=25 π= 1 3 Ο (9.1) 2 β25=2168 ππ‘ 3
Find the volume of the oblique cone. Round your answer to the tenth. π= 1 3 Ο π 2 β π=9.1 β=25 π= 1 3 Ο (9.1) 2 β25=2168 ππ‘ 3
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You Try Find the volume of each cone. Do on your own first!
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You Try π= 1 3 Ο π 2 β π=3.5 β=4 π= 1 3 Ο (3.5) 2 β4=51.3 ππ 3
Find the volume of each cone. π= 1 3 Ο π 2 β π=3.5 β=4 π= 1 3 Ο (3.5) 2 β4=51.3 ππ 3
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