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12.3 Notes: Surface Area of Cylinders, Cones and Pyramids
Date: 12.3 Notes: Surface Area of Cylinders, Cones and Pyramids Lesson Objective: Find surface areas of cylinders, cones and pyramids. CCSS: G.MG.3 Apply geometric methods to solve problems You will need: calculator This is Jeopardy!!!: This is the surface area. Take attendance; go over Jeopardy question: 8 min.
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Lateral Area, L: The area of one ∆ multiplied by the # of ∆s
Lesson 1: Pyramids Lateral Area, L: The area of one ∆ multiplied by the # of ∆s Base Area, B: The area of the polygon base; B = bh, ½ bh Surface Area, S: S = L + B Pull a stick to have someone read: 2 min.; total = 10
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Find the lateral and surface areas.
Lesson 1: Pyramids Find the lateral and surface areas. Pull a stick to have someone read: 2 min.; total = 10
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Find the lateral and surface areas.
Lesson 1: Pyramids Find the lateral and surface areas. l 8 Pull a stick to have someone read: 2 min.; total = 10
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l ² = 8² + 15² l ² = 289 Find the lateral and surface areas.
Lesson 1: Pyramids Find the lateral and surface areas. l ² = 8² + 15² l ² = 289 l l = 17 8 Pull a stick to have someone read: 2 min.; total = 10
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l ² = 8² + 15² l ² = 289 Find the lateral and surface areas.
Lesson 1: Pyramids Find the lateral and surface areas. l ² = 8² + 15² l ² = 289 l l = 17 8 L = (½·16·17)·4 = 544 Pull a stick to have someone read: 2 min.; total = 10
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l ² = 8² + 15² l ² = 289 Find the lateral and surface areas.
Lesson 1: Pyramids Find the lateral and surface areas. l ² = 8² + 15² l ² = 289 l l = 17 8 L = (½·16·17)·4 = 544 B = 16·16 = 256 Pull a stick to have someone read: 2 min.; total = 10
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l ² = 8² + 15² l ² = 289 Find the lateral and surface areas.
Lesson 1: Pyramids Find the lateral and surface areas. l ² = 8² + 15² l ² = 289 l l = 17 8 L = (½·16·17)·4 = 544 B = 16·16 = 256 S = = 800 ft² Pull a stick to have someone read: 2 min.; total = 10
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Lateral Area: L = πrl, l = slant height Base Area: B = πr2
Lesson 2: Cones Lateral Area: L = πrl, l = slant height Base Area: B = πr2 Surface Area: S = L + B, or S = πrl + πr2 Pull a stick to have someone read: 2 min.; total = 10
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Find the lateral and surface areas. Give answer in terms of π.
Lesson 2: Cones Find the lateral and surface areas. Give answer in terms of π. Pull a stick to have someone read: 2 min.; total = 10
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Lesson 2: Cones Find the lateral and surface areas. Give answer in terms of π. l ² = 6² + 8² l ² = 100 l = 10 Pull a stick to have someone read: 2 min.; total = 10
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Lesson 2: Cones Find the lateral and surface areas. Give answer in terms of π. l ² = 6² + 8² l ² = 100 l = 10 L = πrl = π·8·10 = 80π Pull a stick to have someone read: 2 min.; total = 10
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Lesson 2: Cones Find the lateral and surface areas. Give answer in terms of π. l ² = 6² + 8² l ² = 100 l = 10 L = πrl = π·8·10 = 80π B = π·8² = 64π Pull a stick to have someone read: 2 min.; total = 10
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Lesson 2: Cones Find the lateral and surface areas. Give answer in terms of π. l ² = 6² + 8² l ² = 100 l = 10 L = πrl = π·8·10 = 80π B = π·8² = 64π S = 80π + 64π = 144π cm² Pull a stick to have someone read: 2 min.; total = 10
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Surface Area, S: S = L + 2B or S = 2πrh + 2πr2.
Lesson 3: Cylinders Lateral Area, L: L = 2πrh Base Area: B = πr2 Surface Area, S: S = L + 2B or S = 2πrh + 2πr2. Pull a stick to have someone read: 2 min.; total = 10
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Find the lateral and surface areas. Give answer in terms of π.
Lesson 3: Cylinders Find the lateral and surface areas. Give answer in terms of π. Pull a stick to have someone read: 2 min.; total = 10
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Find the lateral and surface areas. Give answer in terms of π.
Lesson 3: Cylinders Find the lateral and surface areas. Give answer in terms of π. L = 2π·8·10 = 160π Pull a stick to have someone read: 2 min.; total = 10
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Find the lateral and surface areas. Give answer in terms of π.
Lesson 3: Cylinders Find the lateral and surface areas. Give answer in terms of π. L = 2π·8·10 = 160π B = π·8² = 64π Pull a stick to have someone read: 2 min.; total = 10
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Find the lateral and surface areas. Give answer in terms of π.
Lesson 3: Cylinders Find the lateral and surface areas. Give answer in terms of π. L = 2π·8·10 = 160π B = π·8² = 64π S = 160π + 2·64π = 160π + 128π = 288π in² Pull a stick to have someone read: 2 min.; total = 10
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A right cone with diameter 18 cm and slant height 5 cm.
12.3: Do I Get It? Yes or No Draw the figure. Find the lateral and surface area. Give circular answers in terms of π. A right cone with diameter 18 cm and slant height 5 cm. A cylinder with diameter 4 cm and height 6 cm. A right square pyramid with base edge length 14 cm and slant height 25 cm. Work on DIGI: 5 min.; total = 55 min
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Lesson 2: The Green Bay Cheese Heads
Discuss “Cheeseheads”: 3 min.; total 40, 15 left
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Lesson 2: The Green Bay Cheese Heads
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Lesson 2: The Green Bay Cheese Heads
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Lesson 2: The Green Bay Cheese Heads
Suppose you want to make your own Cheese-head. It will be an equilateral triangular prism with sides 2 feet and depth 8 inches. How much paper will you need to make a Cheesehead? SSR: 1 min., field answers on what needs to be done: 2 min; total = 43, 12 left
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Lesson 2: The Green Bay Cheese Heads
Suppose you want to make your own Cheese-head. It will be an equilateral triangular prism with sides 2 feet and depth 8 inches. How much paper will you need to make a Cheesehead? Draw a diagram with measures. Calculate the surface area. Work on problem: 4 min.; go over answer: 3 min.; total 50
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