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Alternating signs means we have (-1)n-1 power.
Make a T-chart and find a pattern with the difference tests. 1st level Difference Test. Linear equation with a slope of 2. What needs to be done to 2, 4, 6, 8 to get 1, 3, 5, 7? What needs to be done to 1, 4, 9, 16 to get 2, 5, 10, 17? 2nd level Difference Test. Quadratic equation
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Do you see a pattern?
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The k values are 1 bigger than the powers on the 2.
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Notice that all the properties creates summations that all start at k = 1 and ends with n.
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n = n = Find each sum. Property #2 and #6. Property #1. Property #3.
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Property #2, #3, and #4. n = Property #7, #6, and #1.
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Property #2. Property #5. n = Not k = 1, Property #5
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1st level difference test.
a40 = 2 + 4(40 – 1) n = 40 a1 = 2 +4 +4 +4 +4 d = 4 a40 = 2 + 4(39) = 158 Treat the terms like points, as we did in Sect. 9.1, ( 4, 20 ) and ( 13, 65 ). The difference, d, is the same as the slope. Find the slope between the 2 points. Find a1, use ( 4, 20 ) and ( 1, a1 ) with the slope formula.
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This is a visual approach to solving this problem
This is a visual approach to solving this problem. Make consecutive blanks for each term. a1 ____, ____, ____, ____, ____, ____, ____, ____, ____, ____, ____, ____, ____ Make an equation from 20 to 65 with the 9 d’s. Now subtract the d value backwards for the 1st term.
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101 n a1 a150 = ? a1 an d = -50 n = ? 101 times how many groups?
101 ( 50 ) = 5050 101 Build the formula. Where did the numbers come from? These two formulas go hand in hand. n a1 d = 11 a150 = ? +11 +11 +11 +11 a1 an d = -50 n = ? Solve for n. Find these values.
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Make an equation from 36 to 16 with the 2 r’s.
*3 *3 *3 Make an equation from 36 to 16 with the 2 r’s. ____, ____, ____, ____, ____ With two r values gives us 2 equations.
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n = 10 a1 = 5 r = 2 Multiply both sides by a –r.
This creates opposite terms. Add the equations together and cancel terms. Factor out the S. Factor out the a1 Divide by (1 – r). n = 10 a1 = 5 r = 2
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? ? ( ½ )oo will continue to get smaller until it is zero!
? ? ( ½ )oo will continue to get smaller until it is zero! Dividing by ( ½ ) is the same as multiplying by the reciprocal of 2.
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Determine when a series diverge or converge.
If a finite sum approaches a number L as , we say the infinite geometric series converges. A series diverges when the sum is An infinite geometric series will always converge when This gives us two formulas for geometric series. An infinite geometric series will always diverge when
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2nd STAT – OPS #5 is the sequence formula.
seq(function,variable,starting value,ending value) Find the first 5 terms of 2nd STAT – MATH #5 is the sum formula. Used for Series questions. sum(seq(function,variable,starting value,ending value)) Find
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