Presentation is loading. Please wait.

Presentation is loading. Please wait.

Key Areas covered Resolving a force into two perpendicular components.

Similar presentations


Presentation on theme: "Key Areas covered Resolving a force into two perpendicular components."— Presentation transcript:

1 Key Areas covered Resolving a force into two perpendicular components.
Forces acting at an angle to the direction of movement.

2 What we will do today: Identify how to solve problems when we have two forces acting at different angles (component of forces). Carry out problems on the above

3 Resolution (Rectangular Components) of a Vector
T. Ferns – 4/8/04 LO’s 1.1.5, 1.2.5

4 The horizontal component xh The vertical component xv
Any vector, x, can be resolved into two components at right angles to each other. The horizontal component xh The vertical component xv x xv is equivalent to θ xh

5 sin θ = xv / x xv = x sin θ cos θ = xh / x xh = x cos θ x xv θ xh

6 Force The vertical and horizontal components of a Force vector, F, are, respectively: Fv = F sin θ Fh = F cos θ

7 Velocity (more on this later)
The vertical and horizontal components of a velocity vector, v, are, respectively: vv = v sin θ vh = v cos θ

8 Components of Forces T. Ferns – 13/9/04 LO’s 1.1.5, 1.2.4, 1.2.5

9 This can obviously apply to a force. is equivalent to
In the previous section, a vector was split into horizontal and vertical components. This can obviously apply to a force. is equivalent to Remember that the resultant of a number of forces is the single force which has the same effect, in both magnitude and direction, as the sum of the individual forces. Fv = F sin θ F θ Fh = F cos θ

10 Example 1 A man pulls a garden roller of mass 100 kg with a force of N acting at 30º to the horizontal. If there is a frictional force of 100 N between the roller and the ground, what is the acceleration of the roller along the ground? Solution Fh = F cos θ = 200 cos 30º = N Fun = N – Friction = – 100 = 73.2 N a = Fun / m = / 100 = ms-2 200 N 30º Fh Friction = 100 N

11 Example 2 An oil rig is pulled by two barges as shown. Each barge applies a force of 10 kN. What is the resultant force acting on the rig? Solution: Work out Fh for one barge: Fh = F cos θ = cos 30 = 8660N Then double this to include forces from both barges: 2 x 8660 = N (3 sig fig)

12 Experiment

13 Experiment

14 2004 Qu: 1

15 2009 Qu: 3

16 2001 Qu: 21

17 2001 Qu: 21


Download ppt "Key Areas covered Resolving a force into two perpendicular components."

Similar presentations


Ads by Google