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One Dimensional Motion
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How far something has moved
Distance How far something has moved
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Distance Scalar quantity
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How far something is from its starting position
Displacement How far something is from its starting position
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Displacement A vector quantity
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The interval between two occurrences
Time The interval between two occurrences
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Equal displacement occurs during successive equal time intervals
Uniform Motion Equal displacement occurs during successive equal time intervals
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Velocity is constant during uniform motion
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Distance vs Time Graph
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Slope Slope = rise/run Slope = Dy/Dx
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Slope On a distance vs time graph: Slope = Dd/Dt
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Slope Slope = Dd/Dt Slope = velocity
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Average Velocity v = Dd/Dt v = d1 – d0 t1 – t0
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Displacement df = di + vti d = di + vt
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Distance vs Time Graph
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Distance vs Time Graph
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Acceleration a = Dv/Dt a = vf - vi tf - ti
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Velocity v = v0 + at vf = vi + at
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Displacement d = di + vit + ½ at2
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Displacement df = di + vit + ½ at2
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v2 = vi2 + 2 a(df – di) v2 = vi2 + 2ad
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vf2 = vi2 + 2ad
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v = v0 + at d = d0 + v0t + ½ at2 v2 = v02 + 2ad
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v = v0 + at vf = vi + at
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d = d0 + v0t + ½ at2 df = di + vit + ½ at2
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df = di + vit + ½ at2 d = vit + ½ at2
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v2 = v02 + 2ad vf2 = vi2 + 2ad
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vf = vi + at d = vit + ½ at2 vf2 = vi2+ 2ad
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A ball is dropped from 490 m. Calculate its:
Drill A ball is dropped from 490 m. Calculate its: vf & tair
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A car starts 200. 0 m west of town, and moves at 15 m/s east
A car starts m west of town, and moves at 15 m/s east. 1) write its best equation 2) where will the car be at 10.0 s 3) When will the car be in town
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Determining Instantaneous Velocity
Graph the Dd/Dt data Draw tangent to point of interest Determine slope of tangent
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Velocity vs Time Graphs
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a = slope d = xy or vt d = area
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a = slope = Dy/Dx = Dv/Dt = 62/5 = 12.4 m/s2
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d = area under curve
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Define each of the following
Distance Displacement Speed Velocity Acceleration
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Describe the motion for each series
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Drill: The velocity of a car is increased from 25 to 75 m/s west in 10.0 s. Calculate: a & d
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vf = vi + at d = vit + ½ at2 vf2 = vi2+ 2ad
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Describe the motion between each interval
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Describe the motion of each series
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Draw a position time graph for a person who walks uniformly from the positive side of the origin back thru the origin to the negative side. Repeat for the negative side.
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Make the following conversions: a) 10 m/s to km/hr b) 72 mph to m/s
1.6 km/mile
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Draw a position time graph of a person who walks one block briskly, waits at a traffic light, walks the next block slowly, waits at another light, then runs the last block.
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A truck starts m east of town, and moves at 12 m/s west Find the time & place where the car from the last problem & the truck will be at the same place
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A car increases its velocity from 4.0 m/s to 36 m/s over 4.0 s.
Calculate: a & d
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The same car slows from 36 m/s to 15 m/s in 3.0 s.
1) Calculate the average acceleration & dis
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A car accelerates from 15 m/s to 25 m/s in 125 m.
Calculate its time & acceleration
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Drill:A car is coasting backwards at 3. 0 m/s when its engine starts
Drill:A car is coasting backwards at 3.0 m/s when its engine starts. After 2.5 s the car is going 4.5 m/s. Calculate a & d
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Motion Variables: vi vf a t d
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Make a chart like the one to the right
vi vf a t d
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A car going 4.0 m/s accelerates at 3.0 m/s2 for 4.0 s.
Calculate: vf & d
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A car slows from 44 m/s to 22 m/s in 11 s.
Calculate: a & d
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Motion Affected by Gravity
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A force of attraction between two masses
Gravity A force of attraction between two masses
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This force causes objects to accelerate towards each other
Gravity This force causes objects to accelerate towards each other
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Gravity The acceleration of gravity is relatively constant over the Earth’s surface
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Acceleration of Gravity (ag or g)
9.81 m/s2 Down or (-)
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Any object in air will have a vertical acceleration of
Gravity Any object in air will have a vertical acceleration of -9.81 m/s2
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A ball is dropped from a 0. 49 km cliff
A ball is dropped from a 0.49 km cliff. The acceleration of gravity is -9.8 m/s2. Calculate: vmax & t
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HW: A ball is thrown straight up at 19. 6 m/s
HW: A ball is thrown straight up at 19.6 m/s. The acceleration of gravity is -9.8 m/s2. Calculate: hmax & tair
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Drill: A ball is dropped from a ledge & lands 8.0 s later.
Calculate: hledge & vmax
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Homework Problems: 27 – 30 Page 103
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Drill A ball drops from 0.49 km. Calculate: tair & vmax
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Calculate its tair, vf, & hmax
A man on the ground shoots a gun straight up & the bullet exits the barrel at 980 m/s. The acceleration of gravity is -9.8 m/s2. Calculate its tair, vf, & hmax
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A ball was dropped & landed at 70. 0 m/s
A ball was dropped & landed at 70.0 m/s. The acceleration of gravity is -9.8 m/s2. Calculate: d & tair
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A pumpkin was dropped from a plane & stayed in air for 10. 0 s
A pumpkin was dropped from a plane & stayed in air for 10.0 s. The acceleration of gravity is m/s2. Calculate: h & vmax.
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Homework Problems: Page 106
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Calculate its tair, vf, & hmax
A cannon on a 2500 m cliff is fired straight up & the ball exits the barrel at 0.98 km/s. The acceleration of gravity is -9.8 m/s2. Calculate its tair, vf, & hmax
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A ball is shot straight up to a height of 1. 96 km
A ball is shot straight up to a height of km. The acceleration of gravity is -9.8 m/s2. Calculate: tair & vi
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Drill: A car increases its velocity from 36 km/hr to 72 km/hr in 5.0 s. Calculate: a & d
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A car rolling backwards at 5.0 m/s accelerates at
3.0 m/s2 for 4.0 s. Calculate: vfinal & d
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A car rolling backwards at 25. 0 m/s accelerates at 5. 0 m/s2 for 12
A car rolling backwards at 25.0 m/s accelerates at 5.0 m/s2 for 12.0 s. Calculate: vf & d
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Homework Problems: Page 112 & 113
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Drill: A ball is thrown straight up at 9800 cm/s.
Calculate: tair & hmax
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A ball is thrown straight down at 25 m/s & stays in air for 4.0 s.
g = -9.8 m/s2 Calculate: initial height & vf of the ball.
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A ball is thrown straight up to a height of 49 m.
g = -9.8 m/s2 Calculate: vi & tair
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Homework Problems: Page 114
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Drill: A ball is thrown straight sideways & lands in 5. 0 s
Drill: A ball is thrown straight sideways & lands in 5.0 s. Calculate: initial height & vmax down
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Calculate: a & d during that time.
A car rolling backwards at 5.0 m/s accelerates to 11 m/s forward in 4.0 s. Calculate: a & d during that time.
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A car going 36 km/hr slams on brakes, but still hits a tree at 6
A car going 36 km/hr slams on brakes, but still hits a tree at 6.0 km/hr after 1.0 s. Calculate: a & d during that time.
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Drill: A ball is thrown straight up and hits the ground in 6.0 sec.
Calculate: hmax & vi
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Test Date Wednesday 10/25/06
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36 km/hr to 54 km/hr in 5.0 s. Calculate: a & d during that time.
Drill: A car goes from 36 km/hr to 54 km/hr in 5.0 s. Calculate: a & d during that time.
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Matching Stuff Formulas Definitions Units
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Definitions Motion Position Velocity Speed Distance Displacement
Time Acceleration
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Units Displacement Time Velocity Acceleration
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A ball is thrown straight up at 49 m/s. Calculate: tair & hmax
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Calculate: a & d during that time.
A car rolling backwards at 6.0 km/hr accelerates to 30.0 km/hr forward in 6.0 s. Calculate: a & d during that time.
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A ball is thrown straight up to a height of 490 m. Calculate: tair & vi
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