Download presentation
Presentation is loading. Please wait.
Published byCarol Cannon Modified over 5 years ago
1
LEAVING CERT ALGEBRA SUMMARY OF THE SECTIONS IN L.C. ALGEBRA NOTES
1. SIMPLIFY Squaring Rule Division in Algebra Surds
2
NOTES Common (grouping) Quadratic 2. FACTORS Difference of two squares Sum and difference of two cubes
3
NOTES Linear Quadratic Cubic 3. FUNCTIONS AND EQUATIONS 2 unknowns Simultaneous Non-linear Express in terms of
4
NOTES Linear 5. INEQUALITIES Quadratic from Graphs 6. INDICES Single
Double Linear 5. INEQUALITIES Quadratic from Graphs 6. INDICES
5
SECTION 1 SIMPLIFYING
6
NOTES
8
Calculator
9
Calculator
10
x ( x + y ) + y ( x + y )
11
When simplifying surds we use the following :
1. Example: Example: 2. Example: 3. Only like surds can be added or subtracted. 4. Example: Example: 5. Multiplying surds Example: . Example:
12
Example: Irrational Denominator 6. Irrational Denominator Rational Denominator Example: Irrational Denominator Rational Denominator
14
SECTION 2 FACTORS
15
Method 1 Brackets Method 2 Big X Method 3 Guide Number
16
Method 1 Brackets Method 2 Big X Method 3 Guide Number
18
Method 1 Using Factors Method 2 Using Quadratic Formula
19
Method 1 Using Factors Method 2 Using Quadratic Formula
20
Method 1 Using Factors Method 3 Using Quadratic Formula Method 2 Using
21
Method 2 Method 1
23
This rearranging is often called
“changing the subject of the formula” or “express in terms of ”.
25
SECTION 5 INEQUALITIES -1 x -3 3x sign. a also is symbol inequality
The signs 3 6 9 - + Change 1 - 2 - 1 - 3 - 4 2 3 4 5
26
bits. two into up Split 1 - 2 - 1 - 3 - 4 2 3 4 5
27
2. (a) Find the value of 3(2p – q) when p = -4 and q = 5
3(2(-4) – 5) 3( -8 -5) 3(-13) Value is -39 ’04, LCO, Paper 1
28
Method: Get a common denominator
29
Method: Use previous answer and cancel
30
Method: Use previous answer and solve
31
Method: Isolate x Step 1: Take b from both sides Step 2: Divide both sides by a
32
Method: Solve the inequality and then select all appropriate integers for the set
Remember the set of integers Z contains all positive and negative whole numbers and zero. A = 1 2 3 4 5 6 7 -1 -2 -3 -4 -5 8 -6 -7 -8
33
Multiply both sides by 2 Take 1 from both sides Divide both sides by 3 Multiply both sides by -1 Remember this will change the direction of the inequality List the solution set Or show the solution set on the number line 1 2 3 4 5 6 7 -1 -2 -3 -4 -5 8 -6 -7 -8
34
1 2 3 4 5 6 7 -1 -2 -3 -4 -5 8 -6 -7 -8
35
2006 Paper 1: Question 2
36
Solve simultaneously between Equation 1 and Equation 2 to find the values of a and b
37
2006 Paper 1: Question 3
Similar presentations
© 2024 SlidePlayer.com. Inc.
All rights reserved.