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LEAVING CERT ALGEBRA SUMMARY OF THE SECTIONS IN L.C. ALGEBRA NOTES

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1 LEAVING CERT ALGEBRA SUMMARY OF THE SECTIONS IN L.C. ALGEBRA NOTES
1. SIMPLIFY Squaring Rule Division in Algebra Surds

2 NOTES Common (grouping) Quadratic 2. FACTORS Difference of two squares Sum and difference of two cubes

3 NOTES Linear Quadratic Cubic 3. FUNCTIONS AND EQUATIONS 2 unknowns Simultaneous Non-linear Express in terms of

4 NOTES Linear 5. INEQUALITIES Quadratic from Graphs 6. INDICES Single
Double Linear 5. INEQUALITIES Quadratic from Graphs 6. INDICES

5 SECTION 1 SIMPLIFYING

6 NOTES

7

8 Calculator

9 Calculator

10 x ( x + y ) + y ( x + y )

11 When simplifying surds we use the following :
1. Example: Example: 2. Example: 3. Only like surds can be added or subtracted. 4. Example: Example: 5. Multiplying surds Example: . Example:

12 Example: Irrational Denominator 6. Irrational Denominator Rational Denominator Example: Irrational Denominator Rational Denominator

13

14 SECTION 2 FACTORS

15 Method 1 Brackets Method 2 Big X Method 3 Guide Number

16 Method 1 Brackets Method 2 Big X Method 3 Guide Number

17

18 Method 1 Using Factors Method 2 Using Quadratic Formula

19 Method 1 Using Factors Method 2 Using Quadratic Formula

20 Method 1 Using Factors Method 3 Using Quadratic Formula Method 2 Using 

21 Method 2 Method 1

22

23 This rearranging is often called
“changing the subject of the formula” or “express in terms of ”.

24

25 SECTION 5 INEQUALITIES -1 x -3 3x sign. a also is symbol inequality
The signs 3 6 9 - + Change 1 - 2 - 1 - 3 - 4 2 3 4 5

26 bits. two into up Split 1 - 2 - 1 - 3 - 4 2 3 4 5

27 2. (a) Find the value of 3(2p – q) when p = -4 and q = 5
3(2(-4) – 5) 3( -8 -5) 3(-13) Value is -39 ’04, LCO, Paper 1

28 Method: Get a common denominator

29 Method: Use previous answer and cancel

30 Method: Use previous answer and solve

31 Method: Isolate x Step 1: Take b from both sides Step 2: Divide both sides by a

32 Method: Solve the inequality and then select all appropriate integers for the set
Remember the set of integers Z contains all positive and negative whole numbers and zero. A = 1 2 3 4 5 6 7 -1 -2 -3 -4 -5 8 -6 -7 -8

33 Multiply both sides by 2 Take 1 from both sides Divide both sides by 3 Multiply both sides by -1 Remember this will change the direction of the inequality List the solution set Or show the solution set on the number line 1 2 3 4 5 6 7 -1 -2 -3 -4 -5 8 -6 -7 -8

34 1 2 3 4 5 6 7 -1 -2 -3 -4 -5 8 -6 -7 -8

35 2006 Paper 1: Question 2

36 Solve simultaneously between Equation 1 and Equation 2 to find the values of a and b

37 2006 Paper 1: Question 3

38

39


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