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Physics 1A, Section 2 October 28, 2010.

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Presentation on theme: "Physics 1A, Section 2 October 28, 2010."— Presentation transcript:

1 Physics 1A, Section 2 October 28, 2010

2 Quiz Problem 49

3 Quiz Problem 49 Answer: {[k3 + (k1-1 + k2-1)-1]-1 + k4-1]-1

4 Energy Conservation Energy is conserved: K + U + heat + … = constant
Sometimes, mechanical energy is conserved: K + U = mechanical energy = constant Example: ½ mv2 + mgh = constant This often allows a quick solution of a difficult problem.

5 Energy Conservation Energy is conserved: K + U + heat + … = constant
Sometimes, mechanical energy is conserved: K + U = mechanical energy = constant Example: ½ mv2 + mgh = constant This often allows a quick solution of a difficult problem. However, in other cases, mechanical energy is not conserved, so K + U  constant: friction: Energy is lost to heat. inelastic collision: Energy is lost to heat. This is the same thing as saying the force can’t be described by a potential energy; the force is a function of some variable other than position.

6 Energy Conservation Energy is conserved: K + U + heat + … = constant
Sometimes, mechanical energy is conserved: K + U = mechanical energy = constant Example: ½ mv2 + mgh = constant This often allows a quick solution of a difficult problem. However, in other cases, mechanical energy is not conserved, so K + U  constant: friction: Energy is lost to heat. inelastic collision: Energy is lost to heat. This is the same thing as saying the force can’t be described by a potential energy; the force is a function of some variable other than position. In some of those cases, one can resort to using the force to calculate the energy added to the system: energy input = W = ∫F•ds

7 Quiz Problem 50

8 Quiz Problem 50 Answer: v = sqrt(2gh) F = -kx – mmg, to the right
W = -kxs2/2 – mmgxs Wf = 2mmgxs h’ = h – 2mxs xs = [-mmg + sqrt(m2m2g2+2kmgh)]/k

9 Monday, November 1: something to do with potential energy


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