2. ANSWERS WILL BE IN SQUARE UNITS
6.8
Area of a circle
A = p r2
ANSWERS WILL BE IN SQUARE UNITS

3. Find the area. 10 in 7.6 cm 181.5 square cm or 57.76p sq.cm
78.54 square in
or 25p sq. in.

4. A = pr2 C = 2pr A = p 52 10p = 2pr A = 25p or 5 = r A = 78.54 in2
If S has a circumference of 10p inches, find the area of the circle to the nearest hundredth.
A = pr2
C = 2pr
A = p 52
10p = 2pr
A = 25p or
5 = r
A = in2

5. SECTOR: R Q O

6. R
6 cm
60° Q R
7 cm Q
120 °

7. Area of a segment: a segment is a region bound by a chord and its corresponding arc.
The area of a segment is equal to the area of the sector - the area of the triangle. X Y Z

8. R Q
12 yd

9. Given arc XY is 90º and ZX = 8 Find the shaded area. X Z Y
Segment = sector – triangle
= 90π(82) – ½(8)(8)
= 16π – 32 units2 X Y Z

10. Find the area of the shaded region.
A = p22
A = p82
A = p4
A = p64
2 in
A = in2
A = in2
6in
A shaded = A – A= =
60p or in2