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ANSWERS WILL BE IN SQUARE UNITS
6.8 Area of a circle A = p r2 ANSWERS WILL BE IN SQUARE UNITS
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Find the area. 10 in 7.6 cm 181.5 square cm or 57.76p sq.cm
78.54 square in or 25p sq. in.
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A = pr2 C = 2pr A = p 52 10p = 2pr A = 25p or 5 = r A = 78.54 in2
If S has a circumference of 10p inches, find the area of the circle to the nearest hundredth. A = pr2 C = 2pr A = p 52 10p = 2pr A = 25p or 5 = r A = in2
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SECTOR: R Q O
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R 6 cm 60° Q R 7 cm Q 120 °
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Area of a segment: a segment is a region bound by a chord and its corresponding arc.
The area of a segment is equal to the area of the sector - the area of the triangle. X Y Z
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R Q 12 yd
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Given arc XY is 90º and ZX = 8 Find the shaded area. X Z Y
Segment = sector – triangle = 90π(82) – ½(8)(8) = 16π – 32 units2 X Y Z
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Find the area of the shaded region.
A = p22 A = p82 A = p4 A = p64 2 in A = in2 A = in2 6in A shaded = A – A= = 60p or in2
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