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Volume between x^2+y^2=9 and y=(4-x^2)^(½) Rotated about the x-axis

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Presentation on theme: "Volume between x^2+y^2=9 and y=(4-x^2)^(½) Rotated about the x-axis"— Presentation transcript:

1 Volume between x^2+y^2=9 and y=(4-x^2)^(½) Rotated about the x-axis

2 In an xy-plane a volume is represented by perpendicular cirles
Cross seciton centered at y=9 Use y=(x-1)^2 as an edge on [0,2] Use y=(x+1)^2 as an edge on [-1,0]

3 Cross sections are perpendicular to page
Only cross sections with constant y should be used and x values less than 3 All values less than or equal to |ln(x)| Cross sections are triangles 30 deg into the positive z axis

4 Hexagon Cross section where one point is on the line and the distance furthest point to point accross the hexagon is 6 The line that the points follow is on x^2+y^2=16 This volume only exists x=[2(2)^(½),4] in the first quadrant


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