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Gravity Fundamental Forces Newton Cavendish Examples Whiteboards.

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Presentation on theme: "Gravity Fundamental Forces Newton Cavendish Examples Whiteboards."— Presentation transcript:

1 Gravity Fundamental Forces Newton Cavendish Examples Whiteboards

2 Fundamental forces: Fundamental forces: Gravity Weak Nuclear
Always attractive Very weak Acts on all mass Electro-Magnetic Attracts/repels Fairly strong (demo) Acts on charged particles Fundamental forces: Weak Nuclear Explains certain decays Acts in the nucleus Strong Nuclear Binds Nucleons Very strong Very short range

3 Neutrons glue massive nuclei Why there are not an infinite number of elements

4 Newton: Apple falls on his head? Newton knows four things:
Distance apple is from the earth’s center Distance it falls in a second Distance the moon is from the earth’s center Distance it “falls” in a second He concludes there is an inverse square relationship: F  1/r2

5 Newton: r His law of universal gravitation so far: F = Gm1m2 r2 m2 m1
r m1 m2 What to use for G? r = Center to center distance m1 = One of the masses m2 = The other mass G = Universal gravitation constant

6 Cavendish Determines the value of G in 1798 F = Gm1m2 r2
Measures F, both masses, and r G = 6.67 x Nm2/kg2 (units cancel)

7 r F = Gm1m2 r = Center to center distance r2 m1 = One of the masses
m2 = The other mass G = 6.67 x Nm2/kg2 r m1 m2 Example 1 - Find the force of gravity between two 1.0 kg masses whose centers are exactly 1.0 meters apart? Example 2 - What is the force of gravity between a 1.0 kg mass, and the earth? (r = 6.38 x 106 m, mearth = 5.97 x 1024 kg) (check use of scientific notation) Sheet of everything - masses, radii, period of a day

8 Whiteboards: Gravity 1 | 2 | 3 | 4

9 What is the force of gravity between a 5. 2 kg shot and a 250
What is the force of gravity between a 5.2 kg shot and a 250. kg wrecking ball whose centers are 2.45 m distant? F = Gm1m2 r2 1.44 x 10-8 N

10 Another shot is 1. 45 m from the center of a 250
Another shot is 1.45 m from the center of a 250. kg wrecking ball and experiences a force of 1.55 x 10-7 N, what is the mass of the shot? F = Gm1m2 r2 19.5 kg

11 What distance from the center of a 512 kg wrecking ball must a 4
What distance from the center of a 512 kg wrecking ball must a 4.5 kg bowling ball be to experience a force of 1.13 x 10-9 N? F = Gm1m2 r2 11.7 m

12 The moon has a mass of 7. 36 x 1022 kg, and a radius of 1. 74 x 106 m
The moon has a mass of 7.36 x 1022 kg, and a radius of 1.74 x 106 m. What does a 34.2 kg mass weigh on the surface? F = Gm1m2 r2 55.5 N

13 The moon has a mass of 7. 36 x 1022 kg, and a radius of 1. 74 x 106 m
The moon has a mass of 7.36 x 1022 kg, and a radius of 1.74 x 106 m. What mass weighs 25 N on its surface? F = Gm1m2 r2 15 kg

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15 The moon has a mass of 7. 36 x 1022 kg, and a radius of 1. 74 x 106 m
The moon has a mass of 7.36 x 1022 kg, and a radius of 1.74 x 106 m. At what distance from the moon’s center would a 43 kg mass weigh 25 N? F = Gm1m2 r2 2.9 x 106 m


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