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Schedule Today (2/27): Start Chapter 8
Should have read Sections (at least) Friday (3/1): Continue Chapter 8 Should have read through Section 8.7 (at least)
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Acid-Base Question Consider the weak acid HA with Ka = 1.00 x 10–6. 1. Determine the pH of a solution that is 1.00M HA(aq). 2. Determine the pH of a 1.0-L solution to which you add 2.00 moles of HA and 1.00 mole of NaOH. 3. Determine the pH of a 1.0-L solution to which you add 1.00 mole of HA and 1.00 mole of NaOH.
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General Equation for A Buffered Soln.
If [HA]0 and [A–]0 are high enough, no need for this! If [A–]0 = 0, this becomes the equation we saw in Chapter 7.
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General Equation for A Buffered Soln.
rxn: HA + OH– or A– + H3O+ MS: HA, A–, H2O K = “very large” K = Ka or Kb
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Slowly adding a base to a weak acid…
Start with 1.00-L of 1.00M HA (Ka = 1.00 x 10–6) Added NaOH pH change in pH (see earlier work) 3.00 -- 0.05 4.72 1.72 0.10 5.05 0.33 0.15 5.25 0.20 5.40 0.25 5.52 0.12 0.30 5.63 0.11
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Slowly adding a base to a weak acid…
Start with 1.00-L of 1.00M HA (Ka = 1.00 x 10–6) Added NaOH pH change in pH 0.35 5.73 0.10 0.40 5.82 0.09 0.45 5.91 0.50 6.00 0.55 6.09 0.60 6.18 0.65 6.27
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Slowly adding a base to a weak acid…
Start with 1.00-L of 1.00M HA (Ka = 1.00 x 10–6) Added NaOH pH change in pH 0.70 6.37 0.10 0.75 6.47 0.80 6.60 0.13 0.85 6.75 0.15 0.90 6.95 0.20 095 7.27 0.32 1.00 (see earlier work) 10.00 2.73
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Slowly adding a base to a weak acid…
Initial jump in pH, buffer region, jump at equivalence
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