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December 3, 2014 Pages 42 – 43 in Notes

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1 December 3, 2014 Pages 42 – 43 in Notes
Difference of Squares December 3, 2014 Pages 42 – 43 in Notes

2 Warm-Up (Left Side – pg. 42)
Find the square root of the following expressions: 9 25 x2 x4

3 Objective solve quadratic equations and inequalities using graphs, tables, and algebraic methods.[8.D]

4 Essential Question What skills that I have already learned will help me with finding the difference of squares?

5 What is this method for factoring?
If there are only 2 terms, check for difference of squares (2 terms that you can take the square root of). Factor like this… a2 – b2 = (a + b)(a – b) It will always factor into the sum times the difference of the square roots. *Always look for GCF first!

6 Example 1 x2 – 9 Is there a GCF? Remember: a2 – b2 = (a + b)(a – b)
No. Remember: a2 – b2 = (a + b)(a – b) a = x and b = 3 So…factored form is… (x + 3)(x – 3)

7 Example 2 16x2 – 4y2 Is there a GCF?
Yes, 4. So divide both terms: 4(4x2 – y2) Factor inside the ( ) using: a2 – b2 = (a + b)(a – b) a = 2x and b = y So…factored form is… 4(2x + y)(2x – y)

8 Example 3 25x2 – 49y2 Is there a GCF?
No. Factor using: a2 – b2 = (a + b)(a – b) a = 5x and b = 7y So…factored form is… (5x + 7y)(5x – 7y)

9 Example 4 5x2 – 12 Is there a GCF?
No. 5 is not a perfect square so it cannot be factored. This is called a “prime polynomial.” Prime

10 Example 5 x2 + 9 Addition of perfect squares can never be factored!
Prime

11 Example 6 x4 – 16 Is there a GCF? Remember: a2 – b2 = (a + b)(a – b)
No. Remember: a2 – b2 = (a + b)(a – b) a = x2 and b = 4 So…factored form is… (x2 + 4)(x2 – 4) But the second binomial will factor again… (x2 + 4)(x + 2)(x – 2) Completely factored

12 Assignment – Difference of Squares
x2 – 81 2x2 – 8x4 15x2 – 225 x2 – 25 8x4 + 12x2 14x2 – 224y2 x2 + 4 9x2 – 16y2

13 Reflection


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