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Astronomy Picture of the Day (2007 Oct. 15)

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1 Astronomy Picture of the Day (2007 Oct. 15)
Four other spacecraft exit the solar system: Voyager 1 (1977), Voyager 2 (1977), Pioneer 1 (1972), and Pioneer 2 (1974). Explanation: The New Horizons spacecraft took some stunning images of Jupiter earlier this year while on the way out to Pluto. Famous for its Great Red Spot, Jupiter is also known for its regular, equatorial cloud bands, visible through even modest sized telescopes. The above image was taken near Jupiter's terminator, and shows that the Jovian giant possibly has the widest diversity of cloud patterns in our Solar System. On the far left are clouds closest to Jupiter's south pole. Here turbulent whirlpools and swirls are seen in a dark region, dubbed a belt, that rings the planet. Even light colored regions, called zones, show tremendous structure, complete with complex wave patterns. The energy that drives these waves likely comes from below. New Horizons is the fastest space probe ever launched, and is zipping through the Solar System on track to reach Pluto in 2015. Weather pattern, the spot is due to strong circular wind; eddies due to atmosphere turbulence Astronomy Picture of the Day (2007 Oct. 15) Jupiter’s Clouds from New Horizons

2 Dedicated to search for extraterrestrial intelligent life (SETI)
ATA: Allen Telescope Array of 350-dishes when completed. 42 dishes now working Seth Shostak: “I think we will find signals from intelligent civilizations by 2025”

3 Advanced Question Chap. 5, Q30 in P125
Jupitor’s moon Io has an active volcano Pele whose temperature can be as high as 320°C. What is the wavelength of maximum emission for the volcano at this temperature? In what part of the electromagnetic spectrum is this? The average temperature of Io’s surface is -150 °C. Compared with a square meter of surface at this temperature, how much more energy is emitted per second from each square meter of Pele’s surface?

4 Advanced Question Chap. 5, Q30 in P125
Answer: Using Wien’s law. Convert temperature to Kelvins: T= =593 K. Then λmax= m K/593 K = 4.89 X 10-6 m ≈ 5 μm. This is in the infrared Using Steven-Boltzmann’s law. Convert temperature to Kelvin: T= =123 K. Ratio of energy flux = (593/123)4=540. Pele’s surface radiates 540 times as much energy as of Io’s surface per square meter


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