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(7.1) Stoichiometry-Part 2

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Presentation on theme: "(7.1) Stoichiometry-Part 2"— Presentation transcript:

1 (7.1) Stoichiometry-Part 2

2 Mass Calculations We already know that in balanced chemical equations, coefficients represent particles and moles But, if we know molar masses, we can also determine mass relationships

3 Step by Step Solving Stoichiometric Problems
Write out a balanced equation. Convert given mass (or # of particles) to moles. Calculate the moles of required substance based on the moles of given substance. Convert the moles of required substance to mass (or # of particles) based on the question.

4 General Plan for Solving Stoichiometric Calculations
mass of first substance mass of second substance Molar mass n = m M Molar mass m = n x M Mole ratio moles of first substance moles of second substance

5 Sample Problem Phosphorous pentachloride, PCl5, reacts with water to form phosphoric acid, H3PO4(aq), and hydrochloric acid, HCl(aq) PCl5(s) + 4H2O(l)  H3PO4(aq) + 5HCl(aq) a) What mass of PCl5 is needed to react with an excess quantity of H2O to produce 23.5g of HCl? (Ans: 26.9 g) b) How many molecules of H2O are needed to react with 3.87g of PCl5? (Ans: 4.48 x 1022 molecules)

6 Page 244 # 11-14 Page 246 # 15-18 Page 248 # 19-22 (see answers Page 273) Page 244 (#11-13) Page 246 (#15-18) Page 248 (#19-21)


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