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Factoring Trinomials of the Type x2 + bx + c

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Presentation on theme: "Factoring Trinomials of the Type x2 + bx + c"— Presentation transcript:

1 Factoring Trinomials of the Type x2 + bx + c
ALGEBRA 1 LESSON 9-5 (For help, go to Skills Handbook page 721.) List all of the factors of each number. 5-8

2 Factoring Trinomials of the Type x2 + bx + c
ALGEBRA 1 LESSON 9-5 Solutions 1. Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24 2. Factors of 12: 1, 2, 3, 4, 6, 12 3. Factors of 54: 1, 2, 3, 6, 9, 18, 27, 54 4. Factors of 15: 1, 3, 5, 15 5. Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36 6. Factors of 56: 1, 2, 4, 7, 8, 14, 28, 56 7. Factors of 64: 1, 2, 4, 8, 16, 32, 64 8. Factors of 96: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 96 5-8

3 Factoring Trinomials of the Type x2 + bx + c
ALGEBRA 1 LESSON 9-5 a. Factor x2 + 13x – 48. b. Factor n2 – 5n – 24. Identify the pair of factors of –48 that has a sum of 13. Identify the pair of factors of –24 that has a sum of –5. Factors of –48 Sum of Factors 1 and –48 –47 48 and – 2 and –24 –22 24 and – 3 and –16 –13 16 and – Factors of –24 Sum of Factors 1 and –24 –23 24 and – 2 and –12 –10 12 and – 3 and –8 –5 x2 + 13x – 48 = (x + 16)(x – 3) n2 – 5n – 24 = (n + 3)(n – 8) 5-8

4 Factoring Trinomials of the Type x2 + bx + c
ALGEBRA 1 LESSON 9-5 Factor d2 + 17dg – 60g2. Factors of –60 Sum of Factors 1 and –60 –59 60 and – 2 and –30 –28 30 and – 3 and –20 –17 20 and – Find the factors of –60. Identify the pair that has a sum of 17. d2 + 17dg – 60g2 = (d – 3g)(d + 20g) 5-8

5 Factoring Trinomials of the Type x2 + bx + c
ALGEBRA 1 LESSON 9-5 Factor each expression. 1. c2 + 6c x2 – 11x g2 – 2g – 24 4. y2 + y – m2 – 2mn + n2 (c + 3)(c + 3) (x – 2)(x – 9) (g – 6)(g + 4) (y + 11)(y – 10) (m – n)(m – n) 5-8


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