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Tough AP Physics 1 standard Question…
A ball is dropped from rest from a height h above the ground. Another ball is thrown vertically upward from the ground at the instant the first ball is released. Determine the speed of the second ball (V2o) if the two balls are to meet at a height h/2 above the ground. V1o= 0 h/2 h V2o ?
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V1o= 0 The vertical position (y1) of the falling ball h/2 h g x = y1 xo = h vo = 0 a = -g v2o Time for the ball to fall h/2 y1= h/2
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V1o = 0 The vertical position (y2) of the second ball h/2 h g x = y2 xo = 0 vo = v2 a = -g v2o During time t = , the second ball rises to a height h/2 -
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