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Statistics 2 Lesson 2.7 Standard Deviation 2
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Learning Objectives:- Compare distributions and make inferences,
using the shapes of distributions and measures of average and spread, including median and quartiles. Calculate standard deviation.
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The table below shows the scores obtained in 20 netball matches by year 11.
Score x Frequency f 4 5 6 7 3 8 2 9 1 10 20 Calculate the mean and standard deviation. The standard deviation is given by the formula. = fx2 n x2 x = fx n
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We use this table. x f x2 fx fx2 4 5 6 7 3 8 2 9 1 10 20
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We use this table. x f x2 fx fx2 4 16 5 25 6 36 7 3 49 8 2 64 9 1 81
10 100 20
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We use this table. x f x2 fx fx2 4 16 5 25 6 36 24 7 3 49 21 8 2 64 9
81 10 100 20 121
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We use this table. x f x2 fx fx2 4 16 64 5 25 125 6 36 24 144 7 3 49
21 147 8 2 128 9 1 81 10 100 20 121 789
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x f x2 fx fx2 4 16 64 5 25 125 6 36 24 144 7 3 49 21 147 8 2 128 9 1 81 10 100 20 121 789 x = fx n
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x f x2 fx fx2 4 16 64 5 25 125 6 36 24 144 7 3 49 21 147 8 2 128 9 1 81 10 100 20 121 789 x = fx n 121 20 = = 6.05
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x f x2 fx fx2 4 16 64 5 25 125 6 36 24 144 7 3 49 21 147 8 2 128 9 1 81 10 100 20 121 789 = fx2 n x2
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x f x2 fx fx2 4 16 64 5 25 125 6 36 24 144 7 3 49 21 147 8 2 128 9 1 81 10 100 20 121 789 = fx2 n x2 = 789 20 6.052 = 1.69
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The table below shows the scores obtained in 30 netball matches by year 10.
Score x Frequency f 4 6 5 7 8 3 9 2 10 30 Calculate the mean and standard deviation. The standard deviation is given by the formula. = fx2 n x2 x = fx n
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We use this table. x f x2 fx fx2 4 6 5 7 8 3 9 2 10 30
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We use this table. x f x2 fx fx2 4 6 16 5 25 36 7 49 8 3 64 9 2 81 10
100 30
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We use this table. x f x2 fx fx2 4 6 16 24 5 25 36 30 7 49 8 3 64 9 2
81 18 10 100 20 190
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We use this table. x f x2 fx fx2 4 6 16 24 64 5 25 125 36 30 180 7 49
343 8 3 192 9 2 81 18 162 10 100 20 200 190 1266
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x f x2 fx fx2 4 6 16 24 64 5 25 125 36 30 180 7 49 343 8 3 192 9 2 81 18 162 10 100 20 200 190 1266 x = fx n
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x f x2 fx fx2 4 6 16 24 64 5 25 125 36 30 180 7 49 343 8 3 192 9 2 81 18 162 10 100 20 200 190 1266 x = fx n 190 30 = = 6.33
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x f x2 fx fx2 4 6 16 24 64 5 25 125 36 30 180 7 49 343 8 3 192 9 2 81 18 162 10 100 20 200 190 1266 = fx2 n x2
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x f x2 fx fx2 4 6 16 24 64 5 25 125 36 30 180 7 49 343 8 3 192 9 2 81 18 162 10 100 20 200 190 1266 = fx2 n x2 = 1266 30 6.332 = 1.46
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Year 11 Mean = 6.05 Standard Deviation = 1.69
The means are very similar but year 10 have a slightly better mean. Year 10 also have a slightly lower standard deviation so the dispersion from the mean is slightly smaller. Overall year 10 are a little better and a little more consistent.
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Key Words Spread Mean Standard Deviation
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Copy these formulae into your books.
x = fx n = fx2 n x2
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What are the headings for this table?
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What are the headings for this table?
x f x2 fx fx2 Set the pupils some examples to do.
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