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5.2 Definite Integrals and Areas.
The student will learn about: the definition of the definite integral, the fundamental theorem of calculus, and some applications.
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Introduction We begin this section by calculating areas under curves, leading to a definition of the definite integral of a function. The Fundamental Theorem of Integral Calculus then provides an easier way to calculate definite integrals using indefinite integrals. Finally, we will illustrate the wide variety of applications of definite integrals.
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Definite Integral as a Limit of a Sum.
The Definite Integral may be viewed as the area between the function and the x-axis.
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APPROXIMATING AREA BY RECTANGLES
We may approximate the area under a curve Inscribing rectangles under it. Use rectangles with equal bases and with heights equal to the height of the curve at the left-hand edge of the rectangles.
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Area Under a Curve The following table gives the “rectangular approximation” for the area under the curve y = x 2 for 1 ≤ x ≤ 2, with a larger numbers of rectangles. The calculations were done on a graphing calculator, rounding answers to three decimal places. # Rectangles Sum of Areas 4 8 16 32 64 128 256 512 1024 2048
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Those Responsible. Isaac Newton 1642 -1727
Gottfried Leibniz
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Example 1 5 · 3 – 5 · 1 = 15 – 5 = 10 Make a drawing to confirm your answer. 0 x 4 - 1 y 6
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Example 2 4 Make a drawing to confirm your answer. 0 x 4
Nice red box?
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Fundamental Theorem of Calculus
If f is a continuous function on the closed interval [a, b] and F is any antiderivative of f, then
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Evaluating Definite Integrals
By the fundamental theorem we can evaluate Easily and exactly. We simply calculate
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Definite Integral Properties
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Example 3 9 - 0 = 9 0 x 4 - 2 y 10 Do you see the red box?
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Example 4 There is that red box again?
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Examples 5 This is a combination of the previous two problems
= 9 + (e 6)/2 – 1/3 – (e2)/2 = What red box?
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Numerical Integration on a Graphing Calculator
0 x 3 - 1 y 3 -1 x 6 - 0.2 y 0.5
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Application From past records a management services determined that the rate of increase in maintenance cost for an apartment building (in dollars per year) is given by M ’ (x) = 90x 2 + 5,000 where M is the total accumulated cost of maintenance for x years. Write a definite integral that will give the total maintenance cost through the seventh year. Evaluate the integral. 30 x 3 + 5,000x = 10, ,000 – 0 – 0 = $45,290
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Total Cost of a Succession of Units
The following diagrams illustrate this idea. In each case, the curve represents a rate, and the area under the curve, given by the definite integral, gives the total accumulation at that rate.
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FINDING TOTAL PRODUCTIVITY FROM A RATE
A technician can test computer chips at the rate of –3x2 + 18x + 15 chips per hour (for 0 ≤ x ≤ 6), where x is the number of hours after 9:00 a.m. How many chips can be tested between 10:00 a.m. and 1:00 p.m.?
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Solution - N (t) = –3t t + 15 The total work accomplished is the integral of this rate from t = 1 (10 a.m.) to t = 4 (1 p.m.): Use your calculator = ( ) – ( ) = 117 That is, between 10 a.m. and 1 p.m., 117 chips can be tested.
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Summary. We can evaluate a definite integral by the fundamental theorem of calculus:
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HW
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